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Cloud [144]
1 year ago
11

HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
creativ13 [48]1 year ago
8 0

Answer:

C.

Step-by-step explanation:

trust -.-

MrMuchimi1 year ago
6 0

Answer: probably c

Step-by-step explanation:

i divided it and got 401.063963

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5
valina [46]
I think 28fa haha s an
6 0
2 years ago
A farmer is going to divide her 30 acre farm between two crops. Seed for corn costs $15 per acre. Seed for wheat costs $30 per a
Deffense [45]

Answer:

$3200

Step-by-step explanation:

The total area of land is 30 acre. Let x represent the area in acre that corn is planted and y represent the area in acre that wheat is planted. Therefore:

x + y = 30               (1)

Also, the farmer can spend at most $750 on seeds. Corn cost $15 per acre, maize cost $30 per acre. Hence:

15x + 30y ≤ 750      (2)

Also, x and y > 0

The profit is given by the function:

Profit = 100x + 110y

Graphing equation 1 and equation 2 and solving, we get the points:

(10, 20)

Hence the maximum profit is at:

Max profit = 100(10) + 110(20) = $3200

8 0
3 years ago
What value of x makes this equation true 12x-15=6-3x
Alex

Answer:

x = 1.4 (or 21/15)

Step-by-step explanation:

12x - 15 = 6 - 3x

+3x              +3x

-----------------------

15x - 15 = 6

       +15  +15

-----------------------

15x = 21

/15   /15

----------------------

x = 21/15  or

x = 1.4

6 0
2 years ago
Read 2 more answers
Use the expression 14X + 28Y + 21.. what is the greatest common factor
12345 [234]

Answer:

1

Step-by-step explanation:

None of these numbers are alike terms so the only number left is 1.

4 0
2 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
4 0
2 years ago
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