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marysya [2.9K]
3 years ago
9

How do I turn 35 into a fraction?

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0
Every number is already a fraction, it just may not be written in the fraction form. 35 in the fraction written form is 35/1
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If u, v, and w are nonzero vectors in r 2 , is w a linear combination of u and v?
Tju [1.3M]
Not necessarily. \mathbf u and \mathbf v may be linearly dependent, so that their span forms a subspace of \mathbb R^2 that does not contain every vector in \mathbb R^2.

For example, we could have \mathbf u=(0,1) and \mathbf v=(0,-1). Any vector \mathbf w of the form (r,0), where r\neq0, is impossible to obtain as a linear combination of these \mathbf u and \mathbf v, since

c_1\mathbf u+c_2\mathbf v=(0,c_1)+(0,-c_2)=(0,c_1-c_2)\neq(r,0)

unless r=0 and c_1=c_2.
8 0
3 years ago
6.<br> 1<br> 68<br> 61<br> 2<br> m21 =<br> 3<br> m22= <br> m23 -
Advocard [28]

1 = 51

2= 61

3= 29

Step-by-step explanation:

1) 61+68= 129

180-129= 51

2) 61 is across it so they have the same number

3) 61 +90= 151

180-151= 29

6 0
3 years ago
A sinusoidal carrier wave has an amplitude of 5 volts, a frequency of 1MHz, and zero phase angle. Select the correct carrier wav
Vedmedyk [2.9K]

Answer:

The correct answer is b.

Step-by-step explanation:

The wave equation is given generally as:

c(x, t) = Acos(kx - wt)

Where A = amplitude

k = wave number

w = angular frequency.

x = horizontal distance moves by the wave.

t = time

The options show to us that the wave depends only on t and not (x, t).

Hence, the wave equation becomes:

c(t) = Acos(wt)

Given that:

A = 5 V

f = 1 * 10⁶ Hz

Angular Frequency, w, is given as:

w = 2πf

w = 2 * π * 1 * 10⁶ Hz

w = 2π(1 * 10⁶)

The wave equation becomes:

c(t) = 5cos(2*π*1*10⁶)

The correct answer is b.

6 0
3 years ago
Which best describes the range of the function f(x)=2/3(6)x after it has been reflected over the x axis
shtirl [24]
The range is all real numbers.

The function given simplifies to just f(x) = 4x.

This is just a straight line that is increasing from left to right. If we reflect the line over the x-axis, it is still a line that goes on forever in each direction.

Therefore, the range will be all real numbers.
4 0
3 years ago
Read 2 more answers
Suppose we are given the following information.
Minchanka [31]

Since the product of the slope is -1, hence the lines are perpendicular

<h3>Parallel and Perpendicular lines</h3>

Two lines are known to be parallel if they have the same slope while if two lines are perpendicular if the product of the slope is -1

Given the coordinates of line 1 passing through (0, 6) and (6, 4), the slope is given as;

Slope = 4-6/6-0
Slope = -2/6
Slope = -1/3

Similarly for the coordinate points (-1, -7) and (1, -1).

Slope = -1+7/1+1
Slope of line 2 = 6/2

Slope = 3

Take the product of the slopes

Slope = -1/3 * 3
slope = -1

Since the product of the slope is -1, hence the lines are perpendicular

Learn more on parallel and perpendicular lines here: brainly.com/question/25429151

#SPJ1

5 0
2 years ago
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