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1 year ago

This table shows the number of customers who have come in to Trent’s Hobby Shop each day since he opened the doors.

Mathematics

1 answer:

Alona [7]1 year ago

3 0

Since both the input and the output assume only integer values, the function is classified as discrete.

<h3>What are continuous and discrete variables?</h3>

Continuous variables: Can assume decimal values, hence they are represented by rational numbers.

Discrete variables: Assume only countable values, such as 1, 2, 3, …, hence they are represented by whole numbers, or even integers if it can be negative.

In this problem, all values on the table assume only integer values, hence the function is classified as discrete.

More can be learned about classification of variables at brainly.com/question/16978770

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An above ground swimming pool is leaking. After 1/2 hour the pool has leaked 7/8 of a gallon of water. How many gallons of water

pshichka [43]

7/8 gallon of water/ (1/2 hr)= 1.75 gallons of water/ hr.

The swimming pool is leaking 1.75 gallons of water/ hr.

Hope this helps~

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3 years ago

I am 45 I have 25 ones how many tens do I have

dybincka [34]

Answer:

45+25 is 65 in tens you would 6 tens and five ones does this help idrk

Step-by-step explanation:

4 0

2 years ago

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Which linear inequality is represented by the graph?

stich3 [128]

The linear equality y < 3x + 2 is represented by the graph attached.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An inequality is the non equal comparison of two or more numbers and variables.

The linear equality y < 3x + 2 is represented by the graph attached.

Find out more on equation at: brainly.com/question/2972832

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6 0

1 year ago

Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find

Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk $x^2+y^2\le3$ , I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere $x^2+y^2+z^2=3$ .

a. Let $C$ denote the hemispherical <u>c</u>ap $z=\sqrt{3-x^2-y^2}$ , parameterized by

$\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $C$ to be

$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

Then the upward flux of $\vec F=(2z+2)\,\vec k$ through $C$ is

$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le\sqrt3$ and $0\le v\le2\pi$ . Take the normal to $D$ to be

$\vec s_v\times\vec s_u=-u\,\vec k$

Then the downward flux of $\vec F$ through $D$ is

$\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv$

$=\boxed{-6\pi}$

c. The net flux is then $\boxed{4\sqrt3\pi}$ .

d. By the divergence theorem, the flux of $\vec F$ across the closed hemisphere $H$ with boundary $C\cup D$ is equal to the integral of $\mathrm{div}\vec F$ over its interior:

$\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV$

We have

$\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2$

so the volume integral is

$2\displaystyle\iiint_H\mathrm dV$

which is 2 times the volume of the hemisphere $H$ , so that the net flux is $\boxed{4\sqrt3\pi}$ . Just to confirm, we could compute the integral in spherical coordinates:

$\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi$

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3 years ago

Help me guys please need to finish this ASAP

mezya [45]

Answer:

B Wednesday

Step-by-step explanation: Don't cheat on nwea btw

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2 years ago

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