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2 years ago

Find the solutions to x² = 20.

Mathematics

1 answer:

snow_tiger [21]2 years ago

7 0

Answer:

$x = \pm2 \sqrt 5$

Step-by-step explanation:

$~~~~~~x^2=20\\\\\implies x = \pm\sqrt{20}\\\\\implies x = \pm \sqrt{ 4 \times 5}\\\\\implies x = \pm2 \sqrt 5$

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Let R be a relation on the set of all lines in a plane defined by (l 1 , l 2 ) R line l 1 is parallel to l 2 . Show that R is

MArishka [77]

Answer: hello your question is poorly written below is the complete question

Let L be the set of all lines in XY plane and R be the relation in L defined as R = {(L1, L2): L1 is parallel to L2}. Show that R is an equivalence relation. Find the set of all lines related to the line y = 2x + 4.

answer:

a ) R is equivalence

b) y = 2x + C

Step-by-step explanation:

a) Prove that R is an equivalence relation

Every line is seen to be parallel to itself ( i.e. reflexive ) also

L1 is parallel to L2 and L2 is as well parallel to L1 ( i.e. symmetric ) also

If we presume L1 is parallel to L2 and L2 is also parallel to L3 hence we can also conclude that L1 is parallel to L3 as well ( i.e. transitive )

with these conditions we can conclude that ; R is equivalence

b) show the set of all lines related to y = 2x + 4

The set of all line that is related to y = 2x + 4

y = 2x + C

because parallel lines have the same slopes.

5 0

3 years ago

What is the algebraic expression of one fourth of a number n?

dybincka [34]

1/4n I think I hope this is correct

5 0

3 years ago

6 ( y + 8 ) = 3 ( 2y - 7 )

tester [92]

There is no solutions.

6 ( y + 8 ) = 3 ( 2y - 7 )
6y + 48 = 6y - 21
-48 -48
6y = 6y - 27
+27 +27
33y÷33 = 6y÷33
y=2/11 or 0.18

Hope this helps!

7 0

2 years ago

A certain type of bacteria doubles every 7 hours. If you started with 36 bacteria, how many would you have after 28 hours?

Nimfa-mama [501]

I would have 144 because you just times 4 and 36

6 0

3 years ago

1. If x=3-√3, prove that x² +36 x² = x²

valentina_108 [34]

Answer:

we get $x^2=12-6\sqrt{3}$

Step-by-step explanation:

We are given: $x=3-\sqrt{3}$

We need to find $x^2$

Note: Since question is not clear, I am assuming that we need to find $x^2$

Solving:

$x=3-\sqrt{3} \\Taking \ square \ on \ both \ sides\\x^2=(3-\sqrt{3})^2\\$

We know that $(a-b)^2= a^2-2ab+b^2$

Using formula and simplifying

$x^2=(3)^2-2(3)(\sqrt{3})+(\sqrt{3})^2\\x^2=9-6\sqrt{3} +3\\x^2=12-6\sqrt{3} \\$

So, we get $x^2=12-6\sqrt{3}$

3 0

2 years ago