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2 years ago

34. Samir can rent a moving truck from

Mathematics

1 answer:

pochemuha2 years ago

8 0

The correct option in this case is as shown below:

C. Renting from both companies will cost the same if Samir drives the truck 50 miles.

What is the total rent cost for each company?

The total rent for each company can be determined as the fixed charge plus the variable charge per mile multiplied by the number of miles covered

Let us determine the number of miles which makes Samir indifferent between the two companies

Company's A cost=135+0.50x

Company's B cost=125+0.70x

135+0.50x=125+0.70x

135-125=0.70x-0.50x

10=0.20x

x=10/0.20

x=50

The costs of both companies are the same at 50 miles, above that the cost of company A is cheaper because it has a lower variable charge per mile of $0.50 compared to B's $0.70

Find out more about variable charge on:brainly.com/question/14374943

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Rounded to the nearest hundredth , what is the positive solution to the quadratic equation 0=2x^2+3x-8

elena-14-01-66 [18.8K]

The positive solution to the quadratic equation $2 x^{2}+3 x-8=0$ is x = 1.39

<h3>Solution:</h3>

Given quadratic equation is $2 x^{2}+3 x-8=0$

The general quadratic equation is of form:

$a x^{2}+b x+c=0$

Now comparing the general equation with the given equation we get

a = 2 , b = 3 and c = -8

The formula to determine roots of the quadratic equation is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

On plugging in vlaues, we get

$x=\frac{-3 \pm \sqrt{3^{2}-4 \times 2 \times(-8)}}{2 \times 2}$

$\mathrm{x}=\frac{-3 \pm \sqrt{9-(-64)}}{4}$

On solving we get,

$\begin{array}{l}{\mathrm{x}=\frac{-3 \pm \sqrt{9+64}}{4}} \\\\ {\mathrm{x}=\frac{-3 \pm \sqrt{73}}{4}}\end{array}$

$\mathrm{x}=\frac{-3+\sqrt{73}}{4} \text { OR } \mathrm{x}=\frac{-3-\sqrt{73}}{4}$

x = 1.39 OR x = -2.89

Hence , the positive solution to the quadratic equation is x = 1.39

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4 years ago

What is the value of A when we rewrite

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A because if you subtract by 8 then you will get zero which would be A

Step-by-step explanation:

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