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nikitadnepr [17]
3 years ago
11

F(x) = x+3 and g(x) = x^2 - 2. (f -g)(3t)

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

(f - g)(x) = (x+3) – ( x² –2)

= (x+3) + ( - x²+2)

= – x²+x +5

(f -g)(3t) = - (3t)² + (3t)+5

= - 9t²+3t+5

I hope I helped you^_^

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The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det
Maru [420]

Answer:

0.077994

Step-by-step explanation:

Given that the owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club.

H_0: Mean = 30\\H_a: Mean >30

(Right tailed test)

Sample size = n=250

Sample mean = 30.45

Mean difference =30.45-30=0.45\\

Sample std dev s = 5

Sample std error = \frac{5}{\sqrt{n} } =\frac{5}{\sqrt{250} } \\=0.3163

Test statistic = Mean diff/std error = =\frac{0.45}{0.3163} =1.423

Since population std deviation is not know we use t test

p value = 0.077994

4 0
3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
The volume of a cylinder is 176 π cm and its height is 11 π cm.
Liula [17]

Answer:

r = sqrt(16/pi)

Step-by-step explanation:

Cylinder formula = r^2 x pi x height

176 pi/11pi = 16

16 = r^2 x pi

16/ pi = r^2

r = sqrt(16/pi)

6 0
2 years ago
How do i solve this step by step
AlladinOne [14]

Answer:

4) x^10

Step-by-step explanation:

1) If two numbers have the same base (i.e. x^3 and x^4) and you are multiplying them you just add the exponents. Therefore x^3*x^4 would be x^(3+4) which equals x^7.

2) When dividing similar bases you have to subtract the exponents. If we have x^18÷x^8 that is equivalent to x^(18-8) which gives us x^10.

3) If we have (x^3)^3 we will need to multiply the exponents. Therefore (x^3)^3 is equivalent to x^(3*3) which gives us x^9.

4) (x^2*x^4)^4÷x^8

First do what's in the parentheses,

(x^2*x^4) = x^6

Next do the exponents,

(x^6)^3 = x^18

Lastly the division,

x^18÷x^8 = x^10

x^10 is our answer.

4 0
4 years ago
A 50-gallon rain barrel is filled to capacity. It drains at a rate of 10 gallons per minute. Write an equation to show how much
makvit [3.9K]

Answer:

The quantity of water drain after x min is 50 (0.9)^{x}  

Step-by-step explanation:

Given as :

Total capacity of rain barrel = 50 gallon

The rate of drain = 10 gallon per minutes

Let The quantity of water drain after x min = y

Now, according to question

The quantity of water drain after x min = Initial quantity of water ×  (1-\dfrac{\textrm rate}{100})^{\textrm time}

I.e The quantity of water drain after x min = 50 gallon ×  (1-\dfrac{\textrm 10}{100})^{\textrm x}

or,  The quantity of water drain after x min = 50 gallon × (0.9)^{x}

Hence the quantity of water drain after x min is 50 (0.9)^{x}  Answer

4 0
3 years ago
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