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1 year ago

Consider the reaction:

Chemistry

1 answer:

Fofino [41]1 year ago

4 0

The mass in grams of NH₃ produced from the reaction is 3.4 g

<h3>Balanced equation</h3>

We'll begin by writing the balanced equation for the reaction. This illustrated below:

N₂ + 3H₂ -> 2NH₃

From the balanced equation above,

1 dm³ of N₂ reacted to produced 2 dm³ NH₃

<h3>How to determine the volume of NH₃ produced</h3>

From the balanced equation above,

1 dm³ of N₂ reacted to produced 2 dm³ NH₃

Therefore,

2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃

<h3>How to determine the mass of NH₃ produced</h3>

We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:

22.4 dm³ = 1 mole NH₃

Therefore,

4.48 dm³ = 4.48 / 22.4

4.48 dm³ = 0.2 mole of NH₃

Finally, we shall determine the mass of NH₃ as follow:

Molar mass of NH₃ = 17 g/mol
Mole of NH₃ = 0.2 mole
Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 0.2 × 17

Mass of NH₃ = 3.4 g

Learn more about stoichiometry:

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Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Giv

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Answer: No reaction occurs

Explanation:.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$Al(C_2H_3O_2)_3(aq)+3LiNO_3(aq)\rightarrow Al(NO_3)_3(aq)+3LiC_2H_3O_2(s)$

The complete ionic equation is;

$Al^{3+}(aq)+3C_2H_3O_2^-(aq)+3Li^+(aq)+3NO_3^-(aq)\rightarrow Al^{3+}(aq)+3NO_3^-(aq)+3Li^+(aq)+3C_2H_3O_2^-(aq)$

The ions which are present on both the sides of the equation are are not involved in net ionic equation.

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