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Romashka [77]
3 years ago
13

Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Giv

e the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Li (aq) C2H3O2-(aq) → LiC2H3O2(s) Al3 (aq) 3 NO3-(aq) Li (aq) C2H3O2-(aq) → Al(NO3)3(aq) LiC2H3O2(s) 3 Li (aq) (C2H3O2)33-(aq) → Li3(C2H3O2)3 (s) Al3 (aq) 3 NO3-(aq) → Al(NO3)3(s) No reaction occurs.
Chemistry
1 answer:
RSB [31]3 years ago
5 0

Answer: No reaction occurs

Explanation:.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

Al(C_2H_3O_2)_3(aq)+3LiNO_3(aq)\rightarrow Al(NO_3)_3(aq)+3LiC_2H_3O_2(s)

The complete ionic equation is;

Al^{3+}(aq)+3C_2H_3O_2^-(aq)+3Li^+(aq)+3NO_3^-(aq)\rightarrow Al^{3+}(aq)+3NO_3^-(aq)+3Li^+(aq)+3C_2H_3O_2^-(aq)

The ions which are present on both the sides of the equation are are not involved in net ionic equation.

Hence, there is no net reaction.

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a 3.0 M solution of HCl can be prepared from a 12.0 M solution by diluting 30 L of the 12.0 M solution ith suffient distilled wa
Alex_Xolod [135]
<h3>Answer:</h3>

Final volume is 120 L

<h3>Explanation:</h3>
  • Using the dilution concept, dilution involves adding more solvent to a concentrated solution to make it dilute. This results to a dilute solution with less solute concentration and more solvent.

According to the dilution equation;

M1V1 = M2V2

Where, M1 is the molarity  and V1 is the volume of the concentrated solution, while M2 and V2 are the molarity and volume of the diluted solution respectively.

In this case;

M1 = 12.0 M

V1 = 30 L

M2 = 3.0 M

V2 = ?

Therefore;

V2 = M1V1 ÷ M2

    = (12 × 30) ÷ 3

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Hence, the final volume will be 120 liters

6 0
3 years ago
A cylinder is filled with 10.0 L of gas and a piston is put into it. The initial pressure of the gas is measured to be 273. kPa.
Ann [662]

P2 = 54.6 kPa

Explanation:

Given:

V1 = 10.0 L. V2 = 50.0 L

P1 = 273 kPa. P2 = ?

We can use Boyle's law to solve this problem.

P1V1 = P2V2

Solving for P2,

P2 = (V1/V2)P1

= (10.0 L/50.0 L)(273 kPa)

= 54.6 kPa

5 0
3 years ago
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