Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.
Explanation:
Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.
As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.
According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.
Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.
As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.
Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.
Answer:
4.12 mol
Explanation:
Given data:
Moles of LiOH required = ?
Volume of solution = 4.2 L
Molarity of solution = 0.98 M
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
we will calculate the moles from above given formula.
0.98 M = number of moles / 4.2 L
0.98 M × 4.2 L = number of moles
Number of moles = 0.98 M × 4.2 L
Number of moles = 4.12 mol (M = mol/L)
In order for you to get the answer, please have in mind the following situation: To increase the molar concentration of N2O4(g), 2NO2(g) should also increase for equilibrium to occur. Now, this equation is exothermic. By <span>Le Chatelier's principle, equilibrium constant and reaction constants also come into play in terms of increasing or decreasing the temperature. After that I know you can find the answer. </span>
Answer:
Double displacement reaction
Explanation:
Cuz both the anions and cations from reagents flipped on product side.
Overrides all the other colors of light and green yelow.
