Question

write an equation in slope-intercept form for the line that satisfies each set of conditions passes through (-6,-6) parelle to y=4/3x+8

Answer 1

the parallel linear equation to y = (4/3)*x + 8 that passes through (-6, -6) is:

y = (4/3)*x + 2

How to find the equation of the parallel line?

A general line equation can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Two linear equations are parallel if the slope is the same, but the y-intercept is different.

Then, an equation parallel to y = (4/3)*x  + 8

Will be of the form:

y = (4/3)*x + c

Where c ≠ 8.

Now, we also want our line to pass through the point (-6, -6), then we must have:

-6 = (4/3)*(-6) + c

With that, we can find the value of c.

-6 + 6*(4/3) = c

6*(-1 + 4/3) = c

6*(1/3) = c = 2

Then the parallel linear equation to y = (4/3)*x + 8 that passes through (-6, -6) is:

y = (4/3)*x + 2

If you want to learn more about linear equations, you can read:

brainly.com/question/1884491

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