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Answer and Explanation:
Given : The random variable x has the following probability distribution.
To find :
a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.
b. Calculate the expected value of x.
c. Calculate the variance of x.
d. Calculate the standard deviation of x.
Solution :
First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.25 0 0 0
1 0.20 0.20 1 0.20
2 0.15 0.3 4 0.6
3 0.30 0.9 9 2.7
4 0.10 0.4 16 1.6
∑P(x)=1 ∑xP(x)=1.8 ∑x²P(x)=5.1
a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) The expected value of x is defined as
c) The variance of x is defined as
d) The standard deviation of x is defined as
<h3><u>Answer</u> :</h3>
Let's solve !
<u>Hence, Oprion-D is correct</u> !
Answer:
It is known that 1 pint equals 16 ounces
Step-by-step explanation:
It is known that 1 pint equals 16 ounces. Then we use this data to transform a number of ounces into pints.
Suppose we have x ounces. We want to know how many pints are these x ounces. Then we perform the following operation
Where z pints is the amount equivalent to x ounces