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1 year ago

Is 1/8 equivalent to 2/12

Mathematics

2 answers:

Mnenie [13.5K]1 year ago

8 0

Answer:

Step-by-step explanation:

Check by changing to a common denominator

Deffense [45]1 year ago

3 0

Answer: no

Explanation: start by finding a common denominator in this case it’ll be 24
1 x 3 3 | 2 x 2 4
- = - - | - = -
8 x 3 24. | 12 x 2 24

After this you can see there’s a one number difference

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Zach can read 7pages of a book in 5 minutes at this rate how long will it take him to read 175 pages

AlexFokin [52]

125 minutes. 175 divided by seven is 25 and 25 multiplied by 5 is 125

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3 years ago

Select all expressions that equal -6-(-2)

riadik2000 [5.3K]

Answer:

-6-(-2) is equivalent to

-6 +2

and 2-6

a) and b) are correct options

4 0

3 years ago

Read 2 more answers

Solve the equation. 2(y – 4) = 4 SHOW YOUR WORK!

ahrayia [7]

2(y−4)=4

(2)(y)+(2)(−4)=4

2y+−8=4

2y−8=4

2y−8+8=4+8

2y=12

$\frac{2y}{2}=\frac{12}{2}$

y=6 is correct answer.

Hope this helps!

Thanks!

8 0

3 years ago

Suppose A = {1, 7, 13, 17, 21, 25} and B = {7, ,14, 21, 28, 35, 42}. What is A∩B?

Lubov Fominskaja [6]

$A\cap B=\{7,21\}$

8 0

3 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago