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IrinaK [193]
2 years ago
13

The sum of the measures of the interior angles of a quadrilateral is 360°. If the acute interior angle of the figure measures 75

°, what does the obtuse interior angle measure?
Mathematics
1 answer:
quester [9]2 years ago
3 0
The sum of the interior angles of a quadrilateral is 4 Right Angles or 360 Degrees.

Hope this helps
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If the graph of f(x) = x is shifted up 9 units, what would be the equation of the new graph?
goblinko [34]

Answer:

x+9

Step-by-step explanation:

f(x) = x, going up 9

that is y=x, going up 9

if you wnat to go up, subtract 9 from y

y -9 = x

y=x+9

convert back to f(x)

f(x) = x+9

5 0
3 years ago
Triangle ABC is an obtuse triangle with the obtuse angle at vertex B. Angle A must be
kvv77 [185]
Answer:

Angle A must be acute.

Explanation:

Both angle A and C must be acute. The sum of the angles in a triangle is 180°.

An obtuse angle is more than 90°, so the sum of the remaining 2 angles has to be less than 90°.

Note that it is impossible to have:

<span>2 right angles in a triangle, because <span>90°+90°=180</span>° and the third angle still needs to be added.1 obtuse and 1 right angle in a triangle, their sum is more than 180°2 obtuse angles in a triangle, their sum is more than 180°</span>

It is possible to have an obtuse-angled isosceles triangle, but the vertex angle must be obtuse and the equal base angles will be acute.

8 0
3 years ago
Please help me. Thanks.
never [62]

REPOST IT A BIT CLEARER sorry i was on caps and im to lazy to elete what i wworte and repost it

8 0
3 years ago
Read 2 more answers
Factor completely: <br> x^3 - x^2 - 6x
PSYCHO15rus [73]

Answer:

x(x-3)(x+2)

Step-by-step explanation:

1. Find the GCF (Greatest Common Factor)

GCF=x

2. Factor out the GCF and simplify.

x(x^{2} -x-6)

3. Factor x^{2} -x-6.

Which two numbers add up to -1 and multiply to -6?

<u>-3 and 2</u>

Rewrite the expression using the numbers above.

(x-3)(x+2)

4. Done!

x(x-3)(x+2)

4 0
2 years ago
What are the solutions of the equation x4 + 95x2 – 500 = 0? Use factoring to solve. x = plus-or-minus StartRoot 5 EndRoot and x
Oduvanchick [21]

Answer:

<em>* x ⇒ plus-or-minus StartRoot 5 EndRoot and ±10i *</em>

Step-by-step explanation:

Through factorization;

x^4 + 95x^2 – 500 = 0, ⇒ <em>u^2 ⇒ x^2</em>,

u^2 + 95u - 500 = 0, ⇒<em> factors of -500; -25, 20, -50 * 10, -2 * 250, -5 * 100...</em>

( u )^2 + ( - 5 + 100 ) + ( - 5 * 100 ) = 0,

( u - 5 )( u + 100 ) = 0,

<em>u = 5, and y = - 100</em>

Substitute u back into format x^2;

u = x^2, 5 = x^2, | x | = √5 ⇒ <em>x = - / + √5,</em>

u = x^2, - 100 = x^2, | x | = √- 100 ⇒ <em>x = - / + 10i</em>

<em>* Answer: x ⇒ plus-or-minus StartRoot 5 EndRoot and ±10i *</em>

7 0
3 years ago
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