You may be trying hard to make something difficult out of something easy here.
You have said that a(n) = 8n . (I can't write a subscript 'n'on this site either,
but 'a(n)' will serve the same purpose.)
So . . . (get ready) . . .
a(n) = (8) times (n)
a(1) = 8
a(2) = 16
a(3) = 24
a(4) = 32
a(5) = 40
a(6) = 48
.
.
a(100) = 800
a(101) = 808
.
.
etc.
Answer:
A Rhombus
Step-by-step explanation:
it's a quadrilateral, but its sides aren't congruent
Answer:12 x w = 48
Step-by-step explanation:
the width is 4
<h2>Answer </h2>
Amount (A) = P[1 + (r/100)]n
Principal (P) = ₹ 26400
Time period (n) = 2 years 4 months
Rate % (R) = 15% compounded annually
<h3>Steps </h3>
First, we will calculate Compound Interest (C.I) for the period of 2 years
A = P[1 + (r/100)]n
= 26400[1 + (15/100)]²
= 26400[(100/100) + (15/100)]²
= 26400 × 115/100 × 115/100
= 26400 × 23/20 × 23/20
= 26400 × 1.3225
= 34914
C.I. = A - P
= 34914 - 26400
= 8514
Now, we will find Simple Interest (S.I) for the period of 4 months
Principal for 4 months after C.I. for 2 years = ₹ 34,914
<h3>We know that ,</h3>
S.I = PRT/100
Here T = 4 months = 4/12 years = 1/3 years
S.I. for 4 months = (1/3) × 34914 × (15/100)
= (1/3) × 34914 × (3/20)
= 34914/20
= 1745.70
Total interest for 2 years 4 months = 8514 + 1745.70
= 10259.70
Total amount for 2 years 4 months = 26400 + 10259.70
= ₹ 36659.70
<h3>
So , the correct answer is ₹ 36659.70 . </h3>
Right triangle
Use Sohcahtoa
Given hypothenuse = 10
Adjacent = x
And angle degree of 52
You can use Cosine
Cos(52) = x/10
0.6156614753 = x/10
x = 6.156614753
Round to nearest tenth
Solution: 6.2
