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vlada-n [284]
2 years ago
14

Staci has seven more cats than Taylor. write an expression that illustrates how many cats Staci has. Use x to represent the numb

er of cats that Taiyler has .
Mathematics
2 answers:
Snezhnost [94]2 years ago
5 0
The number of cats that Taiyler has "X" cats
laila [671]2 years ago
4 0

X + 7 is your answer


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Basics test part one
GarryVolchara [31]
Wait so what is the point of this question?
6 0
2 years ago
Pleaseee helpppp:)))
matrenka [14]

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h3><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em></h3>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

No. of families = 75

Out of 75 no. of families had cars = 42

Out of 1, no. of families can have cars

=  \frac{42}{75}

<em><u>Therefore</u></em><em><u>, </u></em>

Out of 200 families, no. of families had cars

= 200 \times  \frac{42}{75}

=200 \times   \frac{14}{25}

= 8 × 14

= 112

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>cars</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>200</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

5 0
2 years ago
The variable q stands for a prime nnumber. Make a factor tree. Then write the prime factorization without expression
Deffense [45]
I have no clue sorry
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B2%7D%5E%7Bx%20%2B%202%7D%20-%20%20%7B2%7D%5E%7B%20x%20%2B%203%7D%20%7D%7B%2
weeeeeb [17]

I suppose you just have to simplify this expression.

(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)

Divide through every term by the lowest power of 2, which would be <em>x</em> + 1 :

… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)

Recall that <em>n</em>ª / <em>n</em>ᵇ = <em>n</em>ª⁻ᵇ, so that we have

… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)

… = (2¹ - 2²) / (2⁰ - 2¹)

… = (2 - 4) / (1 - 2)

… = (-2) / (-1)

… = 2

Another way to get the same result: rewrite every term as a multiple of <em>y</em> = 2ˣ :

… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)

… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)

… = (4<em>y</em> - 8<em>y</em>) / (2<em>y</em> - 4<em>y</em>)

… = (-4<em>y</em>) / (-2<em>y</em>)

… = 2

8 0
3 years ago
Pls helpp
irina1246 [14]
  • you will need 2 busses to only transport the boys.
  • Mark is at (1 + 5/6) miles of his house.
<h3>How many buses would it take to carry only the boys?</h3>

We know that there are (3 + 1/2) groups, such that each group fill one bus.

2/5 of the students are boys, then the number of groups that we can make only with boys is:

(2/5)*(3 + 1/2) = 6/5 + 1/5 = 7/5 = 5/5 + 2/5 = 1 + 2/5

Then you can make one and a little less than a half of a group, which means that you need 1 and 2/5 of a buss to transport the boys, rounding that to the a whole number, you will need 2 busses to only transport the boys.

<h3>How far is Mark from his house?</h3>

The original distance is:

D = (2 + 3/4) miles.

But Mark only covers 2/3 of that distance, then we have:

d = (2/3)*D = (2/3)*(2 + 3/4) miles = (4/3 + 2/4) miles

d = (4/3 + 1/2) miles = (8/6 + 3/6) miles = (1 + 5/6) miles

Mark is at (1 + 5/6) miles of his house.

If you want to learn more about mixed numbers:

brainly.com/question/21610929

#SPJ1

7 0
1 year ago
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