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Viktor [21]
3 years ago
6

Find a counterexample for this statement. A quadrilateral has four congruent sides.

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer:

A Rhombus

Step-by-step explanation:

it's a quadrilateral, but its sides aren't congruent

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Solve the compound inequality 4x – 7 > 5 or 5x + 4 ≤ –6
bija089 [108]

Answer:

inequality form: x \leq -2 or x > 3

interval notation form: (-∞,-2] ∪ (3,∞)

Step-by-step explanation:

I attached a picture that shows all the work. You begin by isolating then solving for x on both sides. Then form a solution using the information found out about x. For example, you can combine the found inequalities for x to solve that x must be GREATER than 3 while being LESS than -2. Using that you can form an line and make a line. Remember, when writing in interval notation form you always begin from the left to the right (in reference) to the number line.

5 0
2 years ago
What is the slope of this line?
shutvik [7]
I think it’s -1 because with rise/run it goes down 2 and over 2 but the line is going down, so it’s negative.
8 0
3 years ago
Read 2 more answers
Are the graphs of the lines in the pair parallel? Explain.
jonny [76]
You need to convert the second equation to slope/intercept form. The first equation is in that form already. Then you can compare  slopes.

-6x + 8y = 14
8y = 6x + 14
y = (3/4)x + 14/8

SO THE SLOPE IS 3/4 which is the same as slope of equation 1

Therfore they are parallel.
7 0
3 years ago
5tanx-2cotx+1=0...... .
Verdich [7]

Step-by-step explanation:

5(tanx)^2 -2 +tanx=0

let tanx=y

5y^2 + y-2=0

y=0.5403 or y= -0.7403

tanx=0.5403

x=arctan(0.5403)

x=28.38°

or

tanx=-0.7403

x=arctan(-0.7403)

x=143.49°

7 0
3 years ago
The line passes through the points ( 7, -7) and ( 6, -5) a. y = -2x + 7 c. y = -2x - 7 b. y = 2x - 21 d. y = 2x - 7
ollegr [7]
Slope = (-5+7)/(6 - 7) = -2

y = mx + b
b = y - mx
b = -7 - (-2)(7)
b = -7 + 14
b = 7

equation
y = -2x + 7

answer
<span>a. y = -2x + 7</span>
5 0
3 years ago
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