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GalinKa [24]
1 year ago
7

F(x)=2x-7, g(x)=X+7 ——- 2

Mathematics
1 answer:
il63 [147K]1 year ago
8 0

The composite function of f(x) and g(x) is given by:

(f ∘ g)(x) = x.

Since the composite function equals x, it means that f(x) and g(x) are inverses of each other.

<h3>What is the question?</h3>

This problem is incomplete, but researching it on a search engine, it asks for the composite function of f(x) and g(x).

<h3>What is the composite function of f(x) and g(x)?</h3>

The composite function of f(x) and g(x) is given by:

(f ∘ g)(x) = f(g(x)).

For this problem, the functions are given as follows:

  • f(x) = 2x - 7.
  • g(x) = 0.5(x + 7).

Hence the composite function is given by:

(f ∘ g)(x) = f(g(x)) = f(0.5(x + 7)) = 2[0.5(x + 7)] - 7 = x + 7 - 7 = x.

Since the composite function equals x, it means that f(x) and g(x) are inverses of each other.

More can be learned about composite functions at brainly.com/question/13502804

#SPJ1

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To find the tangent to the hyperbola \frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} } at (x₀, y₀), we differentiate the equation implicitly to find the equation of the tangent at (x₀, y₀).

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So, \frac{y - y_{0} }{x - x_{0} } = \frac{b^{2} x_{0} }{a^{2} y_{0} }  \\y - y_{0} = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) \\y = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) + y_{0} \\y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2}  }{a^{2} y_{0} } + y_{0}

So, the equation of the tangent line is y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2}  }{a^{2} y_{0} } + y_{0}

Learn more about equation of tangent line here:

brainly.com/question/12561220

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