<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
Answer:
I believe it is B. n<-5
Step-by-step explanation:
Answer:
The average rate of change between these times is 68 miles per hour
Step-by-step explanation:
Here, we are to determine the average rate of change between hour 2 and hour 7
The distance traveled at hour 2 is 140 miles
The distance traveled at hour 7 is 480 miles
So we can say we have two points and we want to know the rate of change between these points
Mathematically, we can represent the rate of change as Δ
Thus, between the two different times, we have;
Δ = (D7-D2)/(T7-T2)
where (T7,D7) = (7,480) and (T2,D2) = (2,140) represents the time and distance at hour 2 and hour 7 respectively
Now inputing the values into the equation, we have;
Δ = (480-140)/(7-2) = 340/5 = 68 miles/hour
Answer:(-2,7)
Step-by-step explanation:
I believe that is ten right?
