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Ludmilka [50]
2 years ago
13

What's h-4/j = k solve for j.

Mathematics
1 answer:
Shtirlitz [24]2 years ago
6 0
H-4/j=k
-4/j=k-h
j=k-h/-4
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The world's most powerful tugboats are built in Finland. One of these boats can do 9.8 × 107 J of work through a distance of 35
kkurt [141]
<span>2.8 x 10^6 N We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that: F * 35m = 9.8 x 10^7 kg*m^2/s^2 Solving for F, gives F * 35m = 9.8 x 10^7 kg*m^2/s^2 F = 9.8 x 10^7 kg*m^2/s^2 / 35m F = 2.8 x 10^6 kg*m/s^2 F = 2.8 x 10^6 N So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
3 0
3 years ago
3(1−2)&lt;33<br> I will give brainliest!,<br> Pls if possible explaine to me how to do ittt
adell [148]

Answer:

I believe it is B. n<-5

Step-by-step explanation:

8 0
3 years ago
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Question 2*
lilavasa [31]

Answer:

The average rate of change between these times is 68 miles per hour

Step-by-step explanation:

Here, we are to determine the average rate of change between hour 2 and hour 7

The distance traveled at hour 2 is 140 miles

The distance traveled at hour 7 is 480 miles

So we can say we have two points and we want to know the rate of change between these points

Mathematically, we can represent the rate of change as Δ

Thus, between the two different times, we have;

Δ = (D7-D2)/(T7-T2)

where (T7,D7) = (7,480) and (T2,D2) = (2,140) represents the time and distance at hour 2 and hour 7 respectively

Now inputing the values into the equation, we have;

Δ = (480-140)/(7-2) = 340/5 = 68 miles/hour

3 0
3 years ago
Write the solution using interval notation: -8 &lt; 2x - 4 &lt; 10
saul85 [17]

Answer:(-2,7)

Step-by-step explanation:

7 0
1 year ago
May someone please help me
Neporo4naja [7]
I believe that is ten right?
7 0
3 years ago
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