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Ludmilka [50]
1 year ago
13

What's h-4/j = k solve for j.

Mathematics
1 answer:
Shtirlitz [24]1 year ago
6 0
H-4/j=k
-4/j=k-h
j=k-h/-4
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I need help, please
oksian1 [2.3K]

Yes,  a rhombus is a rectangle if it has a similar shape of a square.Hope that helped

6 0
3 years ago
What is the upper bound of the function f(x)=4x4−2x3+x−5?
inessss [21]

Answer:

(no global maxima found)

Step-by-step explanation:

Find and classify the global extrema of the following function:

f(x) = 4 x^4 - 2 x^3 + x - 5

Hint: | Global extrema of f(x) can occur only at the critical points or the endpoints of the domain.

Find the critical points of f(x):

Compute the critical points of 4 x^4 - 2 x^3 + x - 5

Hint: | To find critical points, find where f'(x) is zero or where f'(x) does not exist. First, find the derivative of 4 x^4 - 2 x^3 + x - 5.

To find all critical points, first compute f'(x):

d/( dx)(4 x^4 - 2 x^3 + x - 5) = 16 x^3 - 6 x^2 + 1:

f'(x) = 16 x^3 - 6 x^2 + 1

Hint: | Find where f'(x) is zero by solving 16 x^3 - 6 x^2 + 1 = 0.

Solving 16 x^3 - 6 x^2 + 1 = 0 yields x≈-0.303504:

x = -0.303504

Hint: | Find where f'(x) = 16 x^3 - 6 x^2 + 1 does not exist.

f'(x) exists everywhere:

16 x^3 - 6 x^2 + 1 exists everywhere

Hint: | Collect results.

The only critical point of 4 x^4 - 2 x^3 + x - 5 is at x = -0.303504:

x = -0.303504

Hint: | Determine the endpoints of the domain of f(x).

The domain of 4 x^4 - 2 x^3 + x - 5 is R:

The endpoints of R are x = -∞ and ∞

Hint: | Evaluate f(x) at the critical points and at the endpoints of the domain, taking limits if necessary.

Evaluate 4 x^4 - 2 x^3 + x - 5 at x = -∞, -0.303504 and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

-∞ | ∞

-0.303504 | -5.21365

∞ | ∞

Hint: | Determine the largest and smallest values that f achieves at these points.

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

-0.303504 | -5.21365 | global min

∞ | ∞ | global max

Hint: | Finally, remove the endpoints of the domain where f(x) is not defined.

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

-0.303504 | -5.21365 | global min

Hint: | Summarize the results.

f(x) = 4 x^4 - 2 x^3 + x - 5 has one global minimum:

Answer: f(x) has a global minimum at x = -0.303504

5 0
3 years ago
Read 2 more answers
Giving brainliest !! *easy*
lora16 [44]
31.4 bc 3.14 x 2 x 5
4 0
3 years ago
Read 2 more answers
Which of these tables represents a non-linear function?
olchik [2.2K]

Answer:

we conclude that the table ''A 2-column table with 4 rows. Column 1 is labeled x with entries 17, 18, 19, 20. Column 2 is labeled y with entries 16, 17, 19, 20'' represents a non-linear function.

Step-by-step explanation:

The nature of whether a function can be linear or non-linear, we must check how the x and y values of the table change. If the first difference between y-values remains the same (constant first difference), then the table will represent a linear function, otherwise not.

Given the x and y entries of the first table:

x            y

17           20

18           19

19           18

20          17

From the table, it is clear that as x constantly increases by 1 unit, the y-values are also changing constantly by 1 unit. The first difference between y-values remains the same.

i.e. 19-20=-1, 18-19=-1, 17-18=-1

Thus, this table represents a linear function.

Given the x and y entries of the second table:

x            y

17          -16

18          -17

19           -18

20          -19

From the table, it is clear that as x constantly increases by 1 unit, the y-values are also changing constantly by 1 unit. The first difference between y-values remains the same.

i.e. -17-(-16)=-1, -18-(-17)=-1, -19-(-18)=-1

Thus, this table represents a linear function.

Given the x and y entries of the second table:

x            y

17          16

18          17

19           19

20          20

From the table, it is clear that as x constantly increases by 1 unit, but the y-values are not changing constantly. The first difference between y-values does not remain the same.

i.e. 17- 16 = 1, 19 - 17 = 2, 20 - 19 = 1

Thus, this table does not represent a linear function. Hence, it is a non-linear function.

Given the x and y entries of the second table:

x            y

17          -20

18          -19

19           -18

20          -17

From the table, it is clear that as x constantly increases by 1 unit, the y-values are also changing constantly by 1 unit. The first difference between y-values remains the same.

i.e. -19-(-20)=1, -18-(-19)=1, -17-(-18)=1

Thus, this table represents a linear function.

Therefore, we conclude that the table ''A 2-column table with 4 rows. Column 1 is labeled x with entries 17, 18, 19, 20. Column 2 is labeled y with entries 16, 17, 19, 20'' represents a non-linear function.

4 0
2 years ago
8 kids bought a 3 cakes. How many equal parts will need to divide it so that everyone can have it. Easy one! ​
Vladimir79 [104]

Answer:

3/8 is your answer.

Step-by-step explanation:

Given:

<em>8 kids bought a 3 cakes.</em>

Required:

<em>How many equal parts will need to divide it so that everyone can have it.</em>

Solution:

3/8

Hope this helps ;) ❤❤❤

8 0
3 years ago
Read 2 more answers
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