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belka [17]
3 years ago
13

PLEASE HELP ASAP MIDDLE SCHOOL MATH

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

Step-by-step explanation:

area= 1/2 (base1+base²) h

A = {1/2 (5+12)} × 4

A = {1/2 (17)} × 4

A = 8.5×4

A = 34

I think this is right

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Parallel lines e and f are cut by transversal b.
Lunna [17]

Answer:

Its C

Step-by-step explanation:

Just took the test and found out it's not infact 5, but it's 25

8 0
3 years ago
Read 2 more answers
0.9d-2.1f<br> Helpp!!❗‼️
IceJOKER [234]

Step-by-step explanation:

0.9(17) -2.7(3) =

15.3-8.1

=7.2

8 0
3 years ago
What is the volume of the cube?
DENIUS [597]

Answer:

d) 343 cm^3

Step-by-step explanation:

Because you are talking about volume of a cube, that means all sides are equal. The equation for volume is length x width x height. Since all sides of the cube are equal and you are given the height, 7 cm, you will need to multiply 7 three times. Your equation would be 7 x 7 x 7. Then, 7 x 7 is 49 and 49 x 7 is 343. Don't forget, because we are talking volume, to put the cubed. So, your answer is 343 cm^3.

3 0
3 years ago
One satellite is scheduled to be launched from Cape Canaveral in Florida, and another launching is scheduled for Vandenberg Air
Lisa [10]

Answer:

P(A) = 0.45

P(B) = 0.32

Step-by-step explanation:

Given

P(A) > P(B)

P(A\ u\ B) = 0.626

P(A\ n\ B) = 0.144

Required

Find P(A) and P(B)

We have that:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

and

P(A\ n\ B) = P(A) * P(B) --- (2)

The equations become:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

0.626 = P(A) + P(B) - 0.144

Collect like terms

P(A) + P(B) = 0.626 + 0.144

P(A) + P(B) = 0.770

Make P(A) the subject

P(A) = 0.770 - P(B)

P(A\ n\ B) = P(A) * P(B) --- (2)

0.144 = P(A) * P(B)

P(A) * P(B) = 0.144

Substitute: P(A) = 0.770 - P(B)

[0.770 - P(B)] * P(B) = 0.144

Open bracket

0.770P(B) - P(B)^2 = 0.144

Represent P(B) with x

0.770x - x^2 = 0.144

Rewrite as:

x^2 - 0.770x + 0.144 = 0

Expand

x^2 - 0.45x - 0.32x + 0.144 = 0

Factorize:

x[x - 0.45] - 0.32[x - 0.45]= 0

Factor out x - 0.45

[x - 0.32][x - 0.45]= 0

Split

x - 0.32= 0 \ or\ x - 0.45= 0

Solve for x

x = 0.32\ or\ x = 0.45

Recall that:

P(B) = x

So, we have:

P(B) = 0.32 \ or \ P(B) = 0.45

Recall that:

P(A) = 0.770 - P(B)

So, we have:

P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45

P(A) = 0.45 \ or\ P(A) =0.32

Since:

P(A) > P(B)

Then:

P(A) = 0.45

P(B) = 0.32

6 0
3 years ago
I need help learning how to solve this problem please.
Radda [10]

we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.

now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\stackrel{\textit{Hometown}}{(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})}\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\qquad&#10;\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-6+8}{2}~~,~~\cfrac{-7+6}{2} \right)\implies \left(\cfrac{2}{2}~,~\cfrac{-1}{2} \right)\implies \stackrel{\textit{Emily starts off}}{\left(1~,-\frac{1}{2} \right)}


Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\\\\\\&#10;\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

8 0
3 years ago
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