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emmainna [20.7K]
2 years ago
12

What is the period of the sine funtion y = sin (2x) ?

Mathematics
2 answers:
Margarita [4]2 years ago
8 0

Answer: a

Step-by-step explanation:

2x=2\pi

x=\pi ==> Period: \pi ==> a

Damm [24]2 years ago
4 0

Answer:

Step-by-step explanation:

You can "read" these information from the numbers in your equation:

y = 1 ⋅ sin (2x)

1 is the amplitude meaning that your function is oscillating between

+ 1 and − 1;

2 is used to evaluate the period as:

period = 2π/2 = π

so that one complete oscillation of your sine function is "squeezed" inside the interval 0 to π.

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Answer:

No solution

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Step-by-step explanation:

Given: The system of inequality

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y

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Option 1: (-5,2)

Put x=-5 and y=2

Equation 1                               Equation 2

2>\dfrac{3}{2}(-5)-1                            2

2>-8.5                                    2

    TRUE                                     FALSE

Option 2: (2,2)

Put x=2 and y=2

Equation 1                              Equation 2

2>\dfrac{3}{2}(2)-1                    2

2>2                                           2

  FALSE                                      FALSE

Option 3: (5,2)

Put x=-5 and y=2

Equation 1                            Equation 2

2>\dfrac{3}{2}(5)-1                      2

2>6.5                                           2

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Option 1, 2 and 3 are incorrect because both equation must be true for solution.

Hence, Option 4 is correct no solution.  

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3 years ago
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Answer:

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Answer:

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