The domain of a graph is the possible values of x, the graph can take.
<em>(b) The domain of the relation is the interval [-10,10]</em>
From the attached graph, we have the following observations on the x-axis.
- <em>The value of x starts from -10</em>
- <em>The value of x ends at 10</em>
So, the domain of x is from -10 to 10
Using interval notation, the domain of the relation is: ![[-10,10]](https://tex.z-dn.net/?f=%5B-10%2C10%5D)
Read more about domains at:
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I assume you mean:
P=m/(1+rt) multiply both sides by (1+rt)
P(1+rt)=m perform indicated multiplication on left side
P+Prt=m subtract P from both sides
Prt=m-P divide both sides by Pr
t=(m-P)/(Pr)
Answer:
Range = (7,5,-1,-9)
Point 1 = ( -3, 7)
Point 2 = ( -2, 5)
Point 3 = ( 1, -1)
Point 4 = ( 5, -9)
Step-by-step explanation:
g(x)= 1-2x
The domain is x.
The range is y.
g(x) is the function.
To solve this you just input each number from the domain into the function.
g(x) = 1 - 2(-3)
-2 × -3 = positive 6
It is a positive because a negative multipled by a negative equals a positive. This means it is not 1-6 because it is not a negative, it would be 1+6.
1 + 6 = 7
g(x) = 1 -2(-2)
-2 × -2 = positive 4
1 + 4 = 5
g(x)= 1 - 2(1)
-2 × 1 = -2
Since it is multipled 1 time it will be -2. So the equation is still 1-2.
1 - 2 = -1
g(x)= 1 - 2(5)
-2 × 5= -10
A negative multipled by a positive is a negative.
1 - 10 = -9
Now that you have all the numbers put them in parentheses things like the domain
Range = {7,5,-1,-9}
To graph it you need to put in each point by finding the first number of the domain and range and that is your point.
The first point would be (-3,7) and so on and so forth.
<span>x = 9
Since ZP bisects â OZQ, that means that the measurements for â OZP and â PZQ are the same. So create an equation with their respective values set to each other.
8x - 9 = 5x + 18
Now solve for x
8x - 9 = 5x + 18
Subtract 5x from both sides
3x - 9 = 18
Add 9 to both sides
3x = 27
Divide both sides by 3
x = 9</span>
Answer:
x=27
Step-by-step explanation:
63+90+x=180
63+90=153
180-153= 27