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e-lub [12.9K]
2 years ago
4

Francis was tasked to divide a mixed number by a whole number using the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 only once.

Mathematics
1 answer:
alexandr1967 [171]2 years ago
7 0

The possible quotient expression is 1 2/3 / 4

<h3>How to determine the possible quotient expression?</h3>

The digits are given as:

1, 2, 3, 4, 5, 6, 7, 8, 9

Mixed numbers are represented as:

a b/c

From the list of numbers, we can assume that:

a= 1, b =2 and  c = 3

So, we have:

1 2/3

So, the remaining numbers are:

4, 5, 6, 7, 8, 9

Each of the numbers is an whole number.

So, we can represent the whole number with 4

So, we have:

1 2/3 / 4

Hence, the possible quotient expression is 1 2/3 / 4

Read more about mixed numbers at

brainly.com/question/11205910

#SPJ1

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Write a real-world problem that can be represented by the equation f + 5= -9.
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Answer: Katie is scuba diving at an altitude of -14 ft below sea level. She goes up 5 ft. What altitude is Katie at after she goes up 5 ft?

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What is the length of JK¯¯¯¯¯, to the nearest tenth of a millimeter? 4.5 mm 5.6 mm 8.3 mm 19.9 mm A horizontally-aligned scalene
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5 = side a

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angle B = 62 degrees

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Hope this helps!

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Will drank 3⁄4 of a cup of milk at breakfast and 5⁄6 of a cup of milk at lunch. How much milk did he drink in total?
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5 0
3 years ago
The countries of Europe report that 46% of the labor force is female. The United Nations wonders if the percentage of females in
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Answer:

a) Point estimate p=0.43.

b) The 95% confidence interval for the population proportion of female workers in US is (0.388, 0.473).

c) This confidence interval tells us that, with 95% confidence, the true proportion of females in the U.S. labor force is within 0.388 and 0.473.

d) We can conclude that females do not make up a majority of the US labor force, because we can claim, with 95% confidence, that the true proportion of female workers is under 0.473, which is below 0.5 (or 50%).

Step-by-step explanation:

a) A point estimate can be calculated using the sample results and dividing the amount of female workers in the sample by the sample size:

p=X/n=226/525=0.43

b) We have to calculate a 95% confidence interval for the proportion.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.43*0.57}{525}}\\\\\\ \sigma_p=\sqrt{0.000467}=0.022

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.022=0.042

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.4305-0.042=0.388\\\\UL=p+z \cdot \sigma_p = 0.4305+0.042=0.473

The 95% confidence interval for the population proportion of female workers in US is (0.388, 0.473).

c) This confidence interval tells us that, with 95% confidence, the true proportion of females in the U.S. labor force is within 0.388 and 0.473.

d) We can conclude that females do not make up a majority of the US labor force, because we can claim, with 95% confidence, that the true proportion of female workers is under 0.473, which is below the 50%.

If the confidence interval have included the value 0.5, we could not be sure (with 95% confidence) that female workers do not represent de majority, as there would be possibility that the true proportion is 0.5.

3 0
4 years ago
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