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Jobisdone [24]
3 years ago
12

An overnight train left at 21 55 on a journey that took 9 h 18 mins. Given that the train departed on a Monday, find the day and

time at which it arrived at its destination.
Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer:

7:13 am on Tuesday after adding the time slowly arrange properly and am sure you will get it

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Complete the equation of the line whose slope is -2 and y-intercept is (0,3)<br><br> Please help!
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It’s a no solution problem
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Which statement correctly describes the relationship between the graph of f(x)g(x) and g(x)=f(x−7)?
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Find the volume and surface area of the prism below
Nata [24]

Answer:

a) The volume of the prism is 660 mm³

b) The surface area of the prism is 514 mm²

Step-by-step explanation:

The given prism for which we are to find the volume and the surface area shows the dimensions of the sides

a) To find the volume, we can consider the prism as a composite figure as follows;

The topmost cuboid with dimensions (15 - 2×3) mm, 3 mm, and 9 mm

Therefore, the volume of the topmost cuboid, V₁, is given as follows;

V₁ = 5 mm × 3 mm × 9 mm = 135 mm³

The volume of the cuboid on which the top cuboid rest, V₂, is given as follows;

V₂ = 15 mm × 5 mm × 7 mm = 525 mm³

The volume of the prism, V = V₁ + V₂

Therefore, we have;

V =135 mm³ + 525 mm³ = 660 mm³

The volume of the prism, V = 660 mm³

b) The surface area of the prism is given as follows;

The surface area of the top cuboid, SA₁, is given as follows;

SA₁ = 9 mm × 5 mm + 2 × 3 mm × 9 mm + 2 × 3 mm × 5 mm = 129 mm²

The surface area of the larger cuboid, SA₂, is given as follows;

SA₂ = 2 × 15 mm × 7 mm + 2 × 5 mm × 7 mm + 2 × 3 mm × 5 mm + 15 mm × 5 mm = 385 mm²

The surface area of the prism, SA = SA₁ + SA₂

∴ The surface area of the prism, SA = 129 mm² + 385 mm² = 514 mm²

4 0
2 years ago
What is the distance of the line?<br> Remember the distance formula is (23 - 23) + (42 -
vivado [14]

Answer:

<em>The distance of the line is 10.82</em>

Step-by-step explanation:

Distance Between two Points in the Plane

Given two points A(x1,y1) and B(x2,y2), the distance between them is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The graph clearly shows the points (-5,4) (4,-2), thus the distance is:

d=\sqrt{(4-(-5))^2+(-2-4)^2}=\sqrt{9^2+(-6)^2}

d=\sqrt{81+36}=\sqrt{117}=10.82

The distance of the line is 10.82

4 0
3 years ago
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