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Aloiza [94]
1 year ago
11

In 1742, Christian Goldbach conjectured that every even number greater than 2 can be written as the sum of two prime numbers. Ma

ny mathematicians have tried to prove or disprove this conjecture without succeeding. Show that Goldbach's conjecture is true for each of the following even numbers. (There may be more than one correct answer.)
Mathematics
1 answer:
mezya [45]1 year ago
7 0

The Goldbach's conjecture is true for each of the following even numbers.

(a) 19+5

(b) 43+7

(c) 83+3

(d) 139+5

(e) 199+11

(f) 257+7

<h3>What is Goldbach's conjecture?</h3>

One of the most well-known and enduring open questions in number theory and all of mathematics is Goldbach's conjecture. It says that the sum of two prime numbers is the even natural number higher than two.

<h3>According to the given information:</h3>

A. 24 can be expressed as:

   24 = 19 + 5

B. 50 can be expressed as:

    50 = 43 + 7

C. 86 can be expressed as:

    86  = 83 + 3

D. 144 can be expressed as:

    144 = 139 + 5

E. 210 can be expresses as:

    210 = 199 + 11

F. 264 can be expresses as:

  264 = 257 + 7

The Goldbach's conjecture is true for each of the following even numbers.

(a) 19+5

(b) 43+7

(c) 83+3

(d) 139+5

(e) 199+11

(f) 257+7

To know more about Goldbach's conjecture visit:

brainly.com/question/13193113

#SPJ4

I understand that the question you are looking for is:

In 1742, Christian Goldbach conjectured that every even number greater than 2 can be written as the sum of two prime numbers. Many mathematicians have tried to prove or disprove this conjecture without succeeding. Show that Goldbach’s conjecture is true for each of the following even numbers.

a. 24,

b. 50,

c. 86,

d. 144,

e. 210,

f. 264

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Given: ∠T ≅ ∠V; ST || UV
Novay_Z [31]

The respective missing proofs are; Alternate interior; Transitive property; Converse alternate interior angles theore

<h3>How to complete two column proof?</h3>

We are given that;

∠T ≅ ∠V and ST || UV

From images seen online, the first missing proof is Alternate Interior angles because they are formed when a transversal intersects two coplanar lines.

The second missing proof is Transitive property because angles are congruent to the same angle.

The last missing proof is  Converse alternate interior angles theorem

because two lines are intersected by a transversal forming congruent alternate interior angles, then the lines are parallel.

Read more about Two Column Proof at; brainly.com/question/1788884

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7 0
2 years ago
Please help me find the area of shaded region and step by step​
Bumek [7]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)

A=84-24

A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

7 0
3 years ago
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The answer is 7 because yeah
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ryzh [129]

Answer: 42

Step-by-step explanation: you would do 63 divided by 3 then you would get 21 and do 21×2 and get 42

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What is the volume of a rectangular prism with the dimensions: base 5 8 cm, height 2 3 cm, and length 3 4 cm?
Darina [25.2K]

58 x 23 x 34 = 45356 cm³

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