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Crazy boy [7]
3 years ago
10

%5Cfrac%7B1%7D%7B4%7D%20%20-%207%20%5Cfrac%7B1%7D%7B3%7D%20%20%3D%20%20%5C%5C%208%20%5Cfrac%7B2%7D%7B3%7D%20-%206%20%5Cfrac%7B3%7D%7B10%7D%20%3D%20%20%5C%5C%20please%20%5C%3A%20show%20%5C%3A%20work.%20%5C%3A%20tyia" id="TexFormula1" title="9 \frac{9}{10} + 2 \frac{1}{4} = \\ 6 \frac{1}{4} - 7 \frac{1}{3} = \\ 8 \frac{2}{3} - 6 \frac{3}{10} = \\ please \: show \: work. \: tyia" alt="9 \frac{9}{10} + 2 \frac{1}{4} = \\ 6 \frac{1}{4} - 7 \frac{1}{3} = \\ 8 \frac{2}{3} - 6 \frac{3}{10} = \\ please \: show \: work. \: tyia" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer:

1. 445\frac{1}{2}

2. -1\frac{1}{12}

3. 2\frac{11}{30}

Step-by-step explanation:

1. 9\frac{9}{10} +2\frac{1}{4}

I like to make it an improper fraction first.

\frac{99}{10}+\frac{9}{4}

Now take the LCM. The LCM is 20.

\frac{198}{20} +\frac{45}{20}

Now add them.

\frac{8910}{20}

Make this into a mixed number.

445\frac{1}{2}

That's your answer for number 1.

2. 6\frac{1}{4} -7\frac{1}{3}

Do the same thing as the previous addition problem but subtract instead.

\frac{25}{4} -\frac{22}{3}

\frac{75}{12} -\frac{88}{12}

-\frac{13}{12}=-1\frac{1}{12}

-1\frac{1}{12} is your answer for number 2.

3. 8\frac{2}{3}-6\frac{3}{10}

\frac{26}{3} -\frac{63}{10}

\frac{260}{30}-\frac{189}{30}

\frac{71}{30}=2\frac{11}{30}

2\frac{11}{30} is your answer for number 3.

I hope this helps! Let me know if you need help or if I got anything wrong :)

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I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
3 years ago
Suppose lim f(x)=-1, lim f(x)=-1, and f (-3) is not defined.
cupoosta [38]
Its e all of them hope it helped
4 0
3 years ago
Determine the correct value of 3x+2 when x =5
dedylja [7]

Answer:

17

Step-by-step explanation:

3(5)+2=17

3 0
3 years ago
Read 2 more answers
Debbie and Dave share 75 smarties in the ratio 8 : 7 . How many smarties do they each get?
Fudgin [204]
8+7=15
75 divided by 15 = 5
Each unit =5
8 x 5 = 40, so Debbie gets 40 smarties
7 x 5 = 35, so Dave gets 35 smarties.
7 0
3 years ago
How many solutions does the equation y=x-1 have?
uranmaximum [27]

Answer:

endless solutions they have y=x-1 hopefully that helps you out with your question

6 0
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