Answer:
The mean of the distribution of sample means is 27.6
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 27.6
Standard Deviation, σ = 39.4
We are given that the population is a bell shaped distribution that is a normal distribution.
Sample size, n = 173.
We have to find the mean of the distribution of sample means.
Central Limit theorem:
- It states that the distribution of the sample means approximate the normal distribution as the sample size increases.
- The mean of all samples from the same population will be approximately equal to the mean of the population.
Thus, we can write:
Thus, the mean of the distribution of sample means is 27.6
Answer:
Step 4
Step-by-step explanation:
Bryan wants to ship three medium-sized boxes. Two companies offer different rates.
Company Rate
A
$14.65 per box
B
First box is free, $16.20 for any additional boxes
Bryan used the six steps to solve this problem. On one of the steps, he decided that he would use multiplication and addition to compare the companies and find the best rate. Which step did Bryan use to help him decide?
Answer:
Time = distance/speed. T = 1,200,000,000/28,000. This can be cancelled to 1,200,000/28. Rounding 28 to 30 for the estimate, divide by another ten: 120,000. Then divide by the remaining 3 from 30: 120,000/3 = 40,000. It will take approximately 40,000 hours.
<em>Hope This Helps!</em>
Answer:The equation x² + 7 = 0 has no solution
Explanation:1- using graph:To solve the equation means graphically means to find the x-intercepts.
The attached image shows the graph of the given function.
We can note that there are no x-intercepts. This means that the given function has no real solutions
2- using algebra:To solve the equation algebraically means to find the values of x that would make the equation equal to zero.
Solving the given equation, we would find that:
x² + 7 = 0
x² = -7
x = <span>± </span>√-7
The square root of a negative number will always give imaginary values. This means that the equation has no real solutions
Hope this helps :)
