234÷72 divided with compatible numbers and estimate it

I found some shirts for Jonah that were 40 percent of their regular price I bought him 3 shirts and each one was regularly price

Alekssandra [29.7K]

Answer:

32.40

Step-by-step explanation:

The shirts were 40% of the regular price

The sale price of 1 shirt was

18*40% = sale price

18*.40 =7.20

He bought 3 shirts, so multiply by 3

3 * 7.2 =21.60

He paid 21.60

The price he would have paid without the discount is

18*3 = 54

The savings is

54- 21.60 =32.40

8 0

3 years ago

Evaluate the expression for the given value of the variable. x+1/2+5x−3/6 when x = 3

Elan Coil [88]

So first you would plug 3 into the x values in the equation. (3)+1/2+15-1/2. EVALUATE AND THE ANSWER IS 18!!

4 0

3 years ago

Giving brainliest to CORRECT answer.

gavmur [86]

Answer:

Graph A

Step-by-step explanation:

$y = {x}^{2} - 6x - 7 \\ plug \: y = 0 \\ {x}^{2} - 6x - 7 = 0 \\ {x}^{2} - 6x + 9 = 7 + 9 \\ (x - 3)^{2} = 16 \\ (x - 3) = \pm 4 \\ x = 4 + 3 \: or \: x = - 4 + 3 \\ x = 7 \: or \: x = - 1$

Its mean graph should intersect x axis at x = 7 and x = - 1. This everything is satisfied by graph A.

3 0

3 years ago

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There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

when the temperature is 68 F, the speed of sound in air is approximately 343 meters per second. Approximately how many kilometer

Digiron [165]

Hello!

Since we are given that the speed of sound in the air travels about 343 meters per second, we can multiply 343 meters per second by 5, and then we convert the meters to kilometers.

343 · 5 = 1715 meters per 5 seconds.

1000 meters are equal to 1 kilometer. So, we can divide 1715 by 1000 to convert meters to kilometers.

1715 / 1000 = 1.715

Therefore, the speed of sound in air is about 1.715 kilometers per 5 seconds.

6 0

3 years ago

Read 2 more answers