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sasho [114]
1 year ago
14

What causes a graph to move vertically?

Mathematics
1 answer:
docker41 [41]1 year ago
8 0

The vertical shifts in graphs are caused by a constant added to the output (y - axis).

<h3>What is vertical shift in a graph?</h3>

Vertical shifts are outside changes that affect the output (y- axis) values and shift the function up or down (vertical direction).

Horizontal shifts are inside changes that affect the input (x-) axis values and shift the function left or right

<h3>The cause of vertical shift in a graph</h3>

The vertical shift results from a constant added to the output (y - axis). The graph will move up if the constant added is positive OR it will move down if the constant is negative.

Thus, the vertical shifts in graphs are caused by a constant added to the output (y - axis).

Learn more about vertical shifts in graph here: brainly.com/question/27653529

#SPJ1

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Jamie has 6 coins. Each coin is either a penny or a nickel. How much money does Jamie have?
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He would have 6-30 cents


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What number equals 2/9?​
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So I would say 4/18 but it could probably be 18/81 to
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0.3(n-5)=0.4-0.2 solve for n!
mariarad [96]

Answer:

n = 5.67

Step-by-step explanation:

0.3(n-5)=0.4-0.2

0.3(n-5) = 0.2

Dividing 0.3 both side

\frac{0.3(n-5) }{0.3}  = \frac{0.2}{0.3}

n-5 = 0.67

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4 0
3 years ago
Suppose the average farm owned by the farmers who joined Shays' Rebellion had an area of
zloy xaker [14]

Answer:

d would be the answer

Step-by-step explanation:

i took the test

8 0
2 years ago
Please help asap!!!
sp2606 [1]

Answer:

y=\frac{1}{6} (x+5)^2-4.5

y=\frac{-1}{20} (x-10)^2+1

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3  and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5  and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

(x+5)^2= 4(1.5) (y+4.5)

(x+5)^2= 6(y+4.5)

divide by 6 on both sides

then subtract 4.5 on both sides

y=\frac{1}{6} (x+5)^2-4.5

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4  and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10  and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

(x-10)^2= 4(-5) (y-1)

(x-10)^2= -20(y-1)

divide by -20 on both sides and add 1 on both sides

y=\frac{-1}{20} (x-10)^2+1


8 0
3 years ago
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