Evaluate 8a+3b-10+c^2when a =2,b=5,and c=4
2 answers:
8a+3b-10+c^2 when a=2, b=5, c=4
Plug in numbers for variables:
8(2)+3b-10+c^2 (plug in 2 for a)
8(2)+3(5)-10+c^2 (plug in 5 for b)
8(2)+3(5)-10+4^2 (plug in 4 for c)
Evaluate:
8(2)+3(5)-10+4^2
8(2)+3(5)-10+16 (exponents)
16+3(5)-10+16 (multiplication)
16+15-10+16 (multiplication)
32-10+16 (addition)
22+16 (subtraction)
38 (addition)
Sorry if I messed up. It's hard to keep track of my work without paper because I'm not tech savvy but I'm pretty sure my answer is fine.
Best of luck!
8a+3b-10+c^2when a =2,b=5,and c=4:
(8)(2)+(3)(5)−10+42
=16+(3)(5)−10+42
=16+15−10+42
=31−10+42
=21+42
=21+16
=37
You might be interested in
That will be 40 because the problem is making you multiple
2/1 that the answer to your question
Let x is the odd integer
x +2 is the next odd integer
so sum of an odd integer and the next odd integer:
x + (x+2)
Answer: 99
Step-by-step explanation:
So it would be 4x+108= 180 because it’s a straight line so x=18. For the second one id say A and D