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2 years ago

4(s−3)−4=4+8(2−s)

Mathematics

1 answer:

murzikaleks [220]2 years ago

7 0

Am not really sure but I hope it helps

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Grandpa's age is 7 years less than 6 times Junior's

7nadin3 [17]

Answer:

Junior is 11 and Grandpa is 59

Step-by-step explanation:

G = 6J - 7 Get G by itself

G + J = 70

- J -J

G = -J + 70 Set the two equations equal to each other

6J - 7 = -J + 70

+J +J Add J to both sides

7J - 7 = 70

+ 7 +7 Add 7 to both sides

7J = 77 Divide both sdies by 7

J = 11

If this answer is correct, please make me Brainliest!

3 0

3 years ago

Write 6 3/2 in surd form.

dolphi86 [110]

Answer:

$6\sqrt{6}$

Step-by-step explanation:

Simplify using $a\frac{n}{m} =\sqrt[m]{a^n} :\sqrt{6^3}$

Factor and rewrite the radicand in exponential form: $\sqrt{6^2 x 6}$

Rewrite the expression using $\sqrt[n]{ab} =\sqrt[n]{a}*\sqrt[n]{b} : \sqrt{6^2x\sqrt{6}$

Simplify the radical expression

$6\sqrt{6}$

6 0

2 years ago

Please help me please will give brainliest to anyone

Schach [20]

Answer:

its C

Step-by-step explanation:

3 0

3 years ago

What is 13.023 rounded

V125BC [204]

Answer:

rounded to what tho? nearest tenth? nearest hundreth?

4 0

4 years ago

Read 2 more answers

Use the chart to multiply the binomial by the trinomial.

melomori [17]

Answer:

Option (1) is correct.

The product of $(y+3)(y^2-3y+9)$ is $y^3+27$

Step-by-step explanation:

Given, $(y+3)(y^2-3y+9)$

We have to find the product of above,

We have to multiply each term as ,

$(y+3)(y^2-3y+9)$ can be written as,

$\Rightarrow y(y^2-3y+9)+3(y^2-3y+9)$

When we multiply each term we get,

$\Rightarrow (y^3-3y^2+9y)+(3y^2-9y+27)$

These terms are same as we have filled in table below.

On adding like terms we get,

$\Rightarrow y^3-3y^2+9y+3y^2-9y+27$

$\Rightarrow y^3+27$

Thus, the product of $(y-3)(y^2-3y+9)$ is $y^3+27$

5 0

4 years ago