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3 years ago

Is √36 A rational or irrational number

Mathematics

2 answers:

eimsori [14]3 years ago

6 0

Answer:

It is a rational number because the $\sqrt{36}\\$ is 6.

Step-by-step explanation:

Anestetic [448]3 years ago

3 0

Answer:

Step-by-step explanation:

Rational

√36 = √(6²) = 6

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132=-6+3(1-5p) solve the equation

photoshop1234 [79]

Answer:

p=-9

Step-by-step explanation:

132=-6+3 (1-5p)

-6+3 (1-5p)=132

-6+3 (1-5p)+6=132+6

3(1-5p)=138

3(1-5p)/3=138/3

1-5p=46

1-5p-1=46-1

-5p=45

p=-9

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What is the coefficient of y in the expression 2 ⋅ 3 + 9y? 2 3 6 9

pshichka [43]

The answer is going to be 9. Hope that helped.

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Steven wishes to save for his retirement by depositing $2,000 at the beginning of each year for thirty years. Exactly one year a

Ad libitum [116K]

Step-by-step explanation:

i = interest 3% for 30 years

This is a simple dynamical system for whom the the solutions are given as

$S=R[\frac{(i+1)^n-1}{i}](i+1)$

putting values we get

S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)

= $98005.35

withdrawal of money takes place from one year after last payment

To determine the result we use the present value formula of an annuity date

$P = R\frac{1-(1+i)^{-n}}{i}{i+1}$

we need to calculate R so putting the values and solving for R we get

R= $6542.2356

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3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

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3 years ago

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The distance a car has traveled can be represented by the equation d = 1.4m, where d represents the distance in miles and m repr

ValentinkaMS [17]

Answer:

It is the velocity of the car, the speed.

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