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Mathematics

1 answer:

wariber [46]2 years ago

3 0

Using translation concepts, the y-coordinate of R' will be of -10.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

For this problem, the rule is given by:

(x,y) -> (x + 4, y - 7)

y -> y - 7 means that for the image, the 7 is subtracted from the y-coordinate of the pre-image. The y-coordinate of R is of -3, -3 -7 = -10, hence the y-coordinate of R' will be of -10.

More can be learned about translation concepts at brainly.com/question/28393734

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Tamiku [17]

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Natasha2012 [34]

As we know that the standard equation of circle is ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ , where r is the radius of circle and centre at (h,k) 

Now , as the circle passes through (2,9) so it must satisfy the above equation after putting the values of h and k respectively

${:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}$