Question

What is the equation of the line that passes through the point (-2,-1) and has a slope of 5/2

Answer 1

Answer:

y = (5/2)x + 4

Step-by-step explanation:

We'll look for an equation in the format y = mx + b, where mn is the slope and b the y-intercept (the value of y when x = 0).

y = mx + b

m is (5/2)

y = (5/2)x + b

We need a value of b that will force the line through point (-2,-1).  Enter the point (-2,-1) in the equation and solve for b:

y = (5/2)x + b

-1 = (5/2)(-2) + b

-1 = -5 + b

b = 4

The equation is y = (5/2)x + 4

See attached image.