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1 year ago

9 u + 39 = 6 ( u + 2 ) Someone please helpppp!!!!

Mathematics

2 answers:

Kobotan [32]1 year ago

6 0

Hi!

$\tt{9u+39=6(u+2)}$

Step 1: Distribute 6.

$\tt{9u+39=6u+12$

Step 2: Subtract 39 from both sides.

$\tt{9u=6u-27}$

Step 3: Subtract 6u from both sides.

$\tt{3u=-27}$

Step 4: Divide both sides by 3.

$\tt{u=-9}\checkmark$

Hope that helps!

Have a nice day.

Over [174]1 year ago

5 0

9u+39=6(u+2)
multiply 6 by u and 2
9u+39=6u+12
9u-6u=12-39
3u=-27
u=-27/3
u=-9

hope this helped :)

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Step-by-step explanation:

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Or, 24.4 = L × W

And Perimeter = 2 (Length + Width ) = 2 (L + W )

Or, 20.2 = 2(L + W )

Or , L + W = 10.1 cm ............ 1

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3 years ago

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Step-by-step explanation:

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Answer:

The vector is $\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$ .

Step-by-step explanation:

We can determine the equivalent vector ( $\vec r$ ), dimensionless, by means of the following formula:

$\vec r = \frac{\vec u}{\|\vec u\|} \cdot \|\vec r\|$ (1)

Where:

$\vec u$ - Original vector, dimensionless.

$\|\vec u\|$ - Norm of the original vector, dimensionless.

$\|\vec r\|$ - Norm of the new vector, dimensionless.

The norm of the original vector is determined by the following definition:

$\|\vec u\| = \sqrt{\vec u\,\bullet \,\vec u}$ (2)

If we know that $\vec u = (3, 2, -6)$ , then the norm of the original vector is:

$\|\vec u\| = \sqrt{(3)\cdot (3)+(2)\cdot (2)+(-6)\cdot (-6)}$

$\|\vec u\| = 7$

If we know that $\|\vec r\| = 2$ , then the new vector is:

$\vec r = \frac{2}{7}\cdot (3,2,-6)$

$\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$

The vector is $\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$ .

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3 years ago

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The cost of goods sold for the year was $1,640,070.

5 0

3 years ago

9 u + 39 = 6 ( u + 2 ) Someone please helpppp!!!!​

9 u + 39 = 6 ( u + 2 ) Someone please helpppp!!!!