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Anna [14]
1 year ago
3

Please help me !!!!!​

Mathematics
1 answer:
igomit [66]1 year ago
5 0
Answer is B. 27/7

Reason

I think the set is all rational numbers, 27 / 7 is a rational number.

TT pi is NOT it’s irrational

√ 136 is NOT it’s irrational

.12122122212222….. is NOT it’s irrational
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Hi can someone help me please
tensa zangetsu [6.8K]

Answer: yes

Step-by-step explanation:

3 0
3 years ago
Point A located at -11 and -7 on the coordinate plan is reflected over the X axis to form point B.Then point B is reflected over
Diano4ka-milaya [45]

Answer:

<em>The coordinates of B are (-11,7)</em>

<em>The coordinates of C are (11,7)</em>

Step-by-step explanation:

<u>Reflection of Points</u>

Given a point (x,y), it can be reflected in several ways. Two of the most-used are reflection over the x-axis and reflection over the y-axis.

When the point is reflected over the x-axis, the x-coordinate is unchanged, and the y-coordinate is inverted: (x,y) -> (x,-y).

When the point is reflected over the y-axis, the y-coordinate is unchanged, and the x-coordinate is inverted: (x,y) -> (-x,y).

Point A is located at (-11,-7). It's reflected over the x-axis to form point B whose coordinates are (-11,7).

Then, point B is reflected over the y-axis to form point C with coordinates (11,7).

The coordinates of B are (-11,7)

The coordinates of C are (11,7)

7 0
3 years ago
-1/5c+2+c=1/5(10c-20)
Andreyy89

Let's solve your equation step-by-step.

(− 1 /5 )(c)+2+c= 1 /5  (10c−20)

Step 1: Simplify both sides of the equation.

(− 1 /5 )(c)+2+c= 1 /5 (10c−20)

(− 1 /5 )(c)+2+c=( 1 /5 )(10c)+( 1 /5 )(−20) (Distribute)

−1 /5 c+2+c=2c+−4

( −1 /5 c+c)+(2)=2c−4 (Combine Like Terms)

4 /5 c+2=2c−4

4 /5 c+2=2c−4

Step 2: Subtract 2c from both sides.

4/5 c+2−2c=2c−4−2c

−6 /5 c+2=−4

Step 3: Subtract 2 from both sides.

−6 /5 c+2−2=−4−2

−6 /5 c=−6

Step 4: Multiply both sides by 5/(-6).

( 5 /−6 )*( −6 /5 c)=( 5 /−6 )*(−6)

c=5

Answer:

c=5

7 0
4 years ago
Solve the following system. x 2 - y = 3 x - y = -3 The solution set
Tpy6a [65]
Hello : 
<span>x²- y = 3 ...(1)
 x - y = -3 ...(2)
by (2) : y = x+3
subqct in (1) : x²-x-3 = 3
x²-x-6 =0
(x+2)(x-3) = 0
x+2 =0 or x-3 =0
x=-2 or x=3
if x = -2   y = -2+3 = 1
if x=3      y =3+3 = 6
two solutions : ( -2, 1) , (3,6)</span>
8 0
4 years ago
109,230 in expanded form
Paul [167]
100,000+9,000+200+30
3 0
3 years ago
Read 2 more answers
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