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denpristay [2]
3 years ago
8

-1/5c+2+c=1/5(10c-20)

Mathematics
1 answer:
Andreyy893 years ago
7 0

Let's solve your equation step-by-step.

(− 1 /5 )(c)+2+c= 1 /5  (10c−20)

Step 1: Simplify both sides of the equation.

(− 1 /5 )(c)+2+c= 1 /5 (10c−20)

(− 1 /5 )(c)+2+c=( 1 /5 )(10c)+( 1 /5 )(−20) (Distribute)

−1 /5 c+2+c=2c+−4

( −1 /5 c+c)+(2)=2c−4 (Combine Like Terms)

4 /5 c+2=2c−4

4 /5 c+2=2c−4

Step 2: Subtract 2c from both sides.

4/5 c+2−2c=2c−4−2c

−6 /5 c+2=−4

Step 3: Subtract 2 from both sides.

−6 /5 c+2−2=−4−2

−6 /5 c=−6

Step 4: Multiply both sides by 5/(-6).

( 5 /−6 )*( −6 /5 c)=( 5 /−6 )*(−6)

c=5

Answer:

c=5

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The number of seconds in a year are 31,557,600 seconds, which gives;

There are approximately Pi times 10,000,000 seconds in one <u>year</u>.

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<h3>How can the given statement be completed?</h3>

The number of seconds in one day = 86,400

The number of seconds in one week = 604,800

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Therefore;

\mathbf{\dfrac{The \ number  \ of  \ seconds  \ in \  a \  year}{10,000,000}}  = 3.1557600 \ which  \ is \ close \ to \3.14159 \approx \pi

Which gives;

The number of seconds in a year ≈ π × 10,000,000

The completed statement is therefore;

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