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denpristay [2]
3 years ago
8

-1/5c+2+c=1/5(10c-20)

Mathematics
1 answer:
Andreyy893 years ago
7 0

Let's solve your equation step-by-step.

(− 1 /5 )(c)+2+c= 1 /5  (10c−20)

Step 1: Simplify both sides of the equation.

(− 1 /5 )(c)+2+c= 1 /5 (10c−20)

(− 1 /5 )(c)+2+c=( 1 /5 )(10c)+( 1 /5 )(−20) (Distribute)

−1 /5 c+2+c=2c+−4

( −1 /5 c+c)+(2)=2c−4 (Combine Like Terms)

4 /5 c+2=2c−4

4 /5 c+2=2c−4

Step 2: Subtract 2c from both sides.

4/5 c+2−2c=2c−4−2c

−6 /5 c+2=−4

Step 3: Subtract 2 from both sides.

−6 /5 c+2−2=−4−2

−6 /5 c=−6

Step 4: Multiply both sides by 5/(-6).

( 5 /−6 )*( −6 /5 c)=( 5 /−6 )*(−6)

c=5

Answer:

c=5

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Sauron [17]
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Make y the subject :
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y - 3 = 4(x + 8)      
y - 3 = 4x + 32           // Apply distributive property
y = 4x + 35                // Add 3 to both sides

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Identify Slope : 
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Slope = 4

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Find a point on the line :
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When x = 0, 
y = 4(0) + 35              // Sub x = 0 into the equation 
y = 35                         // Combine like terms
Point = (0, 35)

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Answers :
(a) Slope = 4
(b) One point on the line is (0, 35)
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Answer:

See explanation

Step-by-step explanation:

Consider given statement "If a figure is a cube, then it has eight vertices" in math terms. Let

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Then the statement  "If a figure is a cube, then it has eight vertices"  can be written as

p\Rightarrow q

Converse (q\Rightarrow p): If a figure has eight vertices, then it is a cube.

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A) In a group of 60 students, 15 liked maths only, 20 liked science only and 5 did not like
Paladinen [302]

Part (i)

We have 60 students total, and 5 didn't like any of the two subjects, so that must mean 60-5 = 55 students liked at least one subject.

<h3>Answer: 55</h3>

=========================================================

Part (ii)

We have 15 who like math only, 20 who like science only, and 55 who like either (or both). Let x be the number of people who like both classes.

We can then say

15+20+x = 55

x+35 = 55

x = 55-35

x = 20

This means 20 people liked both subjects

<h3>Answer: 20</h3>

=========================================================

Part (iii)

There are 15 people who like math only, and 20 who like both. Therefore, there are 15+20 = 35 people who like math (and some of these people also like science)

<h3>Answer: 35</h3>

=========================================================

Part (iv)

We'll follow the same idea as the previous part. There are 20 people who like science only and 20 who like both subjects. That yields 40 people total who like science (and some of these people also like math).

<h3>Answer: 40</h3>

=========================================================

Part (v)

We'll draw a rectangle to represent the entire group of 60 students. This is considered the universal set. Inside the rectangle will be two overlapping circles to represent math (M) and science (S).

We'll have 15 go in circle M, but outside circle S to represent the 15 people who like math only. Then we have 20 go in circle S but outside circle M to show the 20 people who like science only. We have another copy of 20 go in the overlapped region between the circles. This is the 20 people who like both classes. And finally, we have 5 go outside both circles, but inside the rectangle. These are the 5 people who don't like either subject.

Note how all of the values in the diagram add up to 60

15+20+20+5 = 60

This helps confirm we have the correct values.

<h3>Answer: See the venn diagram below</h3>

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Answer:

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Step-by-step explanation:

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