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sergiy2304 [10]
3 years ago
8

which cost more. 8 printers priced at $145 per printer or 3 laptop computer priced at $439 per computer? explain.

Mathematics
2 answers:
Elodia [21]3 years ago
8 0
8 printers for $145 each is a total of $1160.

3 laptops for $439 is a total of $1317.

Therefore, the price of 3 laptops for $439 each cost more than 8 printers for $145 each.
Sauron [17]3 years ago
3 0
It helps if you create equations for these problems. 
1.) t= total p= amount of printers 
The equation would be t=145p, since you have to multiply 145 by the amount of printers you are purchasing. 
t=145(8) 
The total for the printers would be $1,160. You can put 145*8 into a calculator.
Now do the same thing for the laptops.
2.) t= total l=laptop
t=439l
t=439(3)
t=$1,317
Three laptops cost more.
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Answer:

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

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Step-by-step explanation:

1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)

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2 Expand by distributing sum groups.

{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

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{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

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4 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2x

​3

​​ y+4x

​2

​​ y

​2

​​ +2xy

​3

​​ +y

​2

​​ (x

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​​ +2xy+y

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​​ )

5 Expand by distributing terms.

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​​ y

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​​ +2x

​3

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​​ y

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​​ +2xy

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​2

​​ x

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​​ +2y

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​​ x+y

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6 Collect like terms.

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​​ y

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​4

​​ +4x

​3

​​ y+6x

​2

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