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Murrr4er [49]
2 years ago
5

Explain the difference between solving an equation with the variables all on one side compared to equations with variables on bo

th sides.
Mathematics
1 answer:
kumpel [21]2 years ago
6 0

An equation having variables on both sides can be solved by bringing all variables to one side.

An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,

5x = 6 + 2x;

3x = 6;

x = 2.

For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,

5y - 3 - 3y = 3y + 5 - 3y;

5y - 3y - 3y + 3y = 5 + 3;

2y = 8;

y = 4;

Thus, methods for solving both kinds of equations is similar.

To learn more about equations, refer to this link:

brainly.com/question/27664510

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Question 8 using radians, find the amplitudeand period of each function and graph it
brilliants [131]
Given

The function is given as

y=3cos\frac{\theta}{3}Required

To determine the amplitude and period.

Explanation

The general trigonometric equation is

y=Acos(Bx-C)+D

where A is the amplitude.

Compare with the given equaiton.

A =3.

Then the amplitude is 3.

Now , find the period.

P=\frac{2\pi}{B}

Substitute the value of B in the expression.

P=\frac{2\pi}{(\frac{1}{3})}=6\piAnswer

Hence the amplitude is 3 and period is

6\pi

The graph of the equation is determined as

5 0
2 years ago
Which point is part of the solution of the inequality y<=|x+4|-3
Whitepunk [10]
<h2>Hello!</h2>

The answer is: The point (0,0) is part of the solution.

<h2>Why?</h2>

To find which point is part of the solution of the inequality, we need to evaluate each of the given points. If the inequality is satisfied, then the point is part of the solution, otherwise, if the inequality is not satisfied, the point is not part of the solution.

We are given the inequality:

y\leq |x+4|-3

So, evaluating we have:

- First point (-2,1)

y\leq |x+4|-3\\\\1\leq |-2+4|-3\\\\1\leq |2|-3\\\\1\leq 2-3\\\\1\leq -1

Now, since 1 is not less or equal to -1, the point (-2,1) is not part of the solution.

- Second point (1,3)

y\leq |x+4|-3\\\\3\leq |1+4|-3\\\\3\leq |5|-3\\\\3\leq 5-3\\\\3\leq 2

Now, since 3 is not less or equal to 2, the point (1,3) is not part of the solution.

- Third point (-4,2)

y\leq |x+4|-3\\\\2\leq |-4+4|-3\\\\2\leq |0|-3\\\\2\leq 0-3\\\\2\leq -3

Now, since 2 is not less or equal to -3, the point (-4,2) is not part of the solution.

- Fourth point (0,0)

y\leq |x+4|-3\\\\0\leq |0+4|-3\\\\0\leq |4|-3\\\\0\leq 4-3\\\\0\leq 1

Now, since 0 is less than 1, the point (0,0) is part of the solution.

Hence, we have that the point (0,0) is part of the solution.

Have a nice day!

3 0
3 years ago
Select the line segment
lina2011 [118]

Answer:

c, line p-q

Step-by-step explanation:

your welcome

5 0
3 years ago
Read 2 more answers
What is the solution to the system of equation -4+3y=-3
Shalnov [3]

Answer:

\huge\boxed{\sf y = 1/3}

Step-by-step explanation:

<h3>Given equation:</h3>

-4 + 3y = -3

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3y = -3 + 4

3y = 1

Divide 3 to both sides

<h3>y = 1/3</h3>

\rule[225]{225}{2}

7 0
2 years ago
Read 2 more answers
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