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Murrr4er [49]
2 years ago
5

Explain the difference between solving an equation with the variables all on one side compared to equations with variables on bo

th sides.
Mathematics
1 answer:
kumpel [21]2 years ago
6 0

An equation having variables on both sides can be solved by bringing all variables to one side.

An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,

5x = 6 + 2x;

3x = 6;

x = 2.

For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,

5y - 3 - 3y = 3y + 5 - 3y;

5y - 3y - 3y + 3y = 5 + 3;

2y = 8;

y = 4;

Thus, methods for solving both kinds of equations is similar.

To learn more about equations, refer to this link:

brainly.com/question/27664510

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Answer:

(3/10,-1/2)

Step-by-step explanation:

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Which of the following is a correct interpretation of the expression 2 +7
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(05.06 LC)The net of an isosceles triangular prism is shown. What is the surface area, in square units, of the triangular prism?
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Answer:

  • C. 152 units²

Step-by-step explanation:

Total surface area is the area of the net.

<u>The rectangles have area:</u>

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<u>The triangles have area:</u>

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Correct choice is C

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An arch has the equation y=-2/81x^2+18. Find it’s maximum height
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Answer:

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Step-by-step explanation:

An arch has the equation y=-2/81x^2+18. Find it’s maximum height

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In engineering, the modulus of elasticity is a way to measure how much an object deforms along an axis when opposing forces are
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Step-by-step explanation:

Consider an engineering material of initial length Lo, Area (A), Modulus of elasticity (E) and applied a force P due to which change in the length of the material is δ2 from it’s original length (Lo)

Initial length of the material is Lo. Hence, at time t = 0 when no force applied on the material the length of the material will not change (i.e., at time t=0, δ1 = 0)

Modulus of elasticity of the material:

E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}

Area of the material:

E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}

A=\frac{P \cdot L_{o}}{E\left[\delta_{2}-\delta_{1}\right]}

Length of the material:

E=\frac{P \cdot L_{0}}{A\left[\delta_{2}-\delta_{1}\right]}

L_{0}=\frac{E \cdot A\left[\delta_{2}-\delta_{1}\right]}{P}

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