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3 years ago

10

Factor this completely P(x)=x^4-256

1 answer:

posledela3 years ago

8 0

$\bf p(x)=x^4-256\qquad \boxed{2^8=256}\qquad p(x)=x^{2\cdot 2}-2^{4\cdot 2}
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p(x)=(x^2)^2-(2^4)^2\implies p(x)=[x^2-2^4]~[x^2+2^4]
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p(x)=[x^2-(2^2)^2]~[x^2+2^4]\implies p(x)=[(x-2^2)(x+2^2)]~[x^2+2^4]
\\\\\\
p(x)=(x-4)(x+4)(x^2+16)$

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Given:

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Original number of peaches = $11\frac{109}{120}$

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