This is what I get not sure if the problem on numerator is together if it is then . X^2+(a^2+1) x^2+a^2+1.
-----------------= ----------------- AX+1. Ax+1 Answer: a^2+x^2+1 ---------------- AX+1
If I wrote the actual problem wrong let me know. This is what I understood.
Answer:
it is in the picture above
Step-by-step explanation:
please give branliest if you want

Use the rational root theorem:

=16,

=1
The dividers of

: 1,2,4,8,16
The dividers of

: 1
Therefore, check the following rational numbers: +-


is a root of the expression, so factor out x-4
Compute

to get the rest of the equation.

Cancel the common factor:

is the final answer
Answer:
y = 14
Step-by-step explanation:
Since AC = BC then the triangle is isosceles and the base angles are congruent, that is
∠A = ∠B = 50°, thus
∠C = 180 - (50 + 50) ← sum of angles in Δ = 180°
= 180 - 100 = 80°, hence
5y + 10 = 80 ( subtract 10 from both sides )
5y = 70 ( divide both sides by 5 )
y = 14
Answer:
Step-by-step explanation:
a|c means that c=a*k k is some positive integer. We know that b|c so b| ak and (a,b)=1, so it must be b|k, i.e k=b*r, r is some positive integer number. Now we have that c=abr, so ab| c.
B) if x and x’ are both solution then we have that
mi | x-x’ for every i.
By a) we have that m1m2...mk| x-x’, so x and x’ are equal by mod od m1m2...mk.