hope that this answers your problem !
To solve this question, we first need to layout the equation
-2 1/2 -(-1 3/4)
Step 1
-2 1/2-(-1 3/4) ... Equation
Step 2
5/2-(-1 3/4) ... Converted to improper fraction
Step 3
5/2-(-7/4) ... converted to improper fraction
Step 4
5/2--7/4 ... Got rid of parenthesis
Step 5
-3/4 ... Subtract
Answer:
-3/4 ... Answer
So the answer for this problem is C, -3/4
3. 6/8/10 is twice the common Pythagorean Triple 3/4/5.
Answer: A. 10
4. 3/4/5 is a Pythagorean Triple because they're three natural numbers that satisfy a²+b²=c^2, here 3²+4²=5².
Answer: C
Non-zero whole numbers are called <em>natural numbers.</em>
<em />
<em />
Answer:
D
Step-by-step explanation:
<em>for </em><em>you </em><em>to </em><em>find </em><em>x </em><em>you </em><em>first </em><em>have </em><em>to </em><em>find </em><em>the </em><em>adjacent</em><em> </em><em>of </em><em>the </em><em>4</em><em>5</em><em>°</em><em> </em><em>angle </em><em>you </em><em>can </em><em>do </em><em>that </em><em>by </em><em>using</em><em> </em><em>the </em><em>other </em><em>triangle.</em><em>u</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>the </em><em>sin </em><em>ratio</em>
<em>sin60=</em><em>opposite</em><em>/</em><em>hypotenuse</em>
<em>sin60=</em><em>a/</em><em>7</em><em>√</em><em>3</em>
<em>a</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>
<em>then </em><em>after </em><em>you </em><em>have </em><em>found</em><em> </em><em>the </em><em>adjacent</em><em> </em><em>you </em><em>can </em><em>use </em><em>the </em><em>cos </em><em>ratio</em>
<em>cos45=</em><em>adjacent/</em><em>hypotenuse</em>
<em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>x</em>
<em>cos45x/</em><em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>cos45</em>
<em>x=</em><em>1</em><em>4</em><em>.</em><em>8</em><em>4</em><em>9</em>
<em>which </em><em>is </em><em>the </em><em>same </em><em>as </em><em>2</em><em>1</em><em>√</em><em>2</em><em> </em><em>over </em><em>2</em>
<em>I </em><em>hope</em><em> this</em><em> helps</em>
9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
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<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
I believe the formula to find the height would be h= 2a/b and if you use that formula and plug in the area (21.7) of each triangle as well as the base (6) then you would get a height of 7.2 cm. I hope this is correct! :)
