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Olin [163]
1 year ago
13

A square rug lies in the middle of a rectangular room. There are 6 feet of uncovered floor on 2 sides of the rug and 2 feet of u

ncovered floor on the other 2 sides. Find a polynomial expression for the area of the rootn in terms of ×, the side length of the rug.
Mathematics
1 answer:
Gekata [30.6K]1 year ago
4 0

The polynomial expression for the area of the room is f(x) = x^2 + 16x + 48.

Here, we are given that the side of the length of the rug = x

Now, the square rug is placed on the rectangular room such that on 2 sides the uncovered floor is 6 meters.

This means that the length of the 2 opposite sides of the rectangle will be (x + 6 + 6) = (x + 12)

Similarly, there is 2 feet of uncovered floor on the other 2 sides, which means that the length of other two opposite sides is- (x + 2 + 2) = (x + 4)

Kindly refer to the diagram below for a better clarity of how we found out the sides.

Now, the area of a rectangle = Length × Breadth

Thus, area of the room = (x + 12) (x + 4)

= x^2 + 4x + 12x + 48

= x^2 + 16x + 48

Thus, the polynomial expression for the area of the room is f(x) = x^2 + 16x + 48

Learn more about quadratic equations here-

brainly.com/question/24334139

#SPJ9

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Two cars travel along a highway at the same speed.
Mazyrski [523]

Answer:

30 mins

Step-by-step explanation:

<em>speed = distance/ time </em>

speed of car A

= 20/ 12 km/ min

= 5/ 3 km/ min

also, speed of car A = speed of car B

speed of car B = 5/ 3 km/ min = 50km / time taken (in mins)

\frac{5}{3}  =  \frac{50}{t}

5t  = 150

t = 30

=> t = 30 mins

6 0
3 years ago
PLEASE HELP!!! So the answer I got was 19.14 however that is not the correct answer. How do I solve this problem. Not sure what
Mamont248 [21]

Check the picture below.

so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.

\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill

3 0
3 years ago
Please help me solve for x
kkurt [141]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The shown pair of angles are Co interior angle pair, therefore the sum of those angles is 180°

\qquad \sf  \dashrightarrow \: 130 \degree + 7x + 1 \degree = 180 \degree

\qquad \sf  \dashrightarrow \: 131 \degree + 7x = 180 \degree

\qquad \sf  \dashrightarrow \:  7x= 180 \degree - 131 \degree

\qquad \sf  \dashrightarrow \:  7x= 49 \degree

\qquad \sf  \dashrightarrow \:  x=49 \degree \div 7

\qquad \sf  \dashrightarrow \:  x=7 \degree

The required value of x is 7°

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