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faust18 [17]
4 years ago
10

William buys a basket of pomegranates on sale for $10 before tax. The sales tax is 17%, percent. What is the total price William

pays for the basket of pomegranates?
Mathematics
1 answer:
maks197457 [2]4 years ago
4 0
William paid $11.70 for the pomegranates because 17% of 10 is 1.7. When you add that back to your original $10, you get $11.70.
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A truck is 250 inches long. A car is 35% shorter than the truck. How long is the car
drek231 [11]

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87.5 inches long

Step-by-step explanation:

250 x 0.35 = 87.5

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1, 1, 4, 7, 8, 8, 8, 11, 15<br> What is the mode of this list of numbers?<br><br> answer asap!!!!
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8

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Iris wants to buy two necklaces, one for her sister and one for herself. The necklace for her sister costs $42.00, and the neckl
Genrish500 [490]

Answer:

$75.60

Step-by-step explanation:

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42 + 28

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Then, to find the price with sales tax, multiply this by 1.08:

70(1.08)

= 75.6

So, the total cost of her purchases was $75.60

4 0
3 years ago
$12,800 at 12% for 3 years find the total amount ?
HACTEHA [7]

Answer:

so first you do

12800*.12 which is  1536

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1536*3=

$4608

so 4608+12800 =

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Mark brainliest

5 0
3 years ago
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Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
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