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1 year ago

Y = x4 - 3x2 + 4

Mathematics

1 answer:

Ostrovityanka [42]1 year ago

3 0

The equation represents both a relation and a function

<h3>How to determine if the equation represents a relation, a function, both a relation and a function, or neither a relation nor a function?</h3>

The equation is given as

y = x^4 - 3x^2 + 4

First, all equations are relations.

This means that the equation y = x^4 - 3x^2 + 4 is a relation

Next, the above equation is an even function.

This is so because

f(x) = f(-x) = x^4 - 3x^2 + 4

This means that the equation is also a relation

Hence, the equation represents both a relation and a function

Read more about functions and relations at:

brainly.com/question/6904750

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I need to turn that into an equation but I cant figure it out.

Nady [450]

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

The equation will be...

$\frac{3x-6}{2} +12$

I don't know if you need to solve it but here you go anyways...

$\frac{3}{2}x+9$

6 0

4 years ago

Giving 40 Points...need help as soon as possible

PIT_PIT [208]

The correct answers are:

The first system matches with (-4, 5);
The second system matches with (2, 2);
The third system matches with (-1, -3);
The fourth system matches with (3, 4);
The fifth system matches with (2, -1); and
The sixth system matches with (-5, 6).

Explanation:

The sixth system is the easiest one to find. We are given the value of x and the value of y in the equations: x=-5 and y=6.

For all other systems, we must solve the system. For the first system:
$\left \{ {{2x-y=-13} \atop {y=x+9}} \right.$

Since we have the y-variable isolated in the second equation, we will use substitution. We substitute this value in place of y in the first equation:
2x-y=-13
2x-(x+9)=-13

Distributing the subtraction sign,
2x-x-9=-13

Combining like terms:
x-9=-13

Add 9 to each side:
x-9+9=-13+9
x=-4

Substitute this into the second equation:
y=x+9
y=-4+9
y=5

The coordinates (-4, 5) represent the solution point.

For the second system:
$\left \{ {{3x+2y=10} \atop {6x-y=10}} \right.$

We can make the coefficients of x the same and use elimination. To do this, we will multiply the first equation by 2:
 $\left \{ {{2(3x+2y=10)} \atop {6x-y=10}} \right. \\ \\ \left \{ {{6x+4y=20} \atop {6x-y=10}} \right.$

Since the coefficients of x are now the same, we can cancel it. They are both positive, so we subtract:
$\left \{ {{6x+4y=20} \atop {-(6x-y=10)}} \right. \\ \\5y=10$

Divide both sides by 5:
5y/5=10/5
y=2

Substitute this into the second equation
6x-y=10
6x-2=10

Add 2 to each side:
6x-2+2=10+2
6x=12

Divide both sides by 6:
6x/6 = 12/6
x=2

The coordinates (2, 2) represent the solution to this system.

For the third system:
$\left \{ {{4x-3y=5} \atop {3x+2y=-9}} \right.$

We can make the coefficients of x the same by multiplying the first equation by 3 and the second by 4:
$\left \{ {{3(4x-3y=5)} \atop {4(3x+2y=-9)}} \right. \\ \\ \left \{ {{12x-9y=15} \atop {12x+8y=-36}} \right.$

Since the coefficients of x are the same, we can cancel them. Since they are both positive, we will subtract:
$\left \{ {{12x-9y=15} \atop {-(12x+8y=-36)}} \right. \\ \\-17y=51$

Divide both sides by -17:
-17y/-17 = 51/-17
y=-3

Substitute this into the first equation:
4x-3y=5
4x-3(-3)=5
4x--9=5
4x+9=5

Subtract 9 from each side:
4x+9-9=5-9
4x=-4

Divide each side by 4:
4x/4 = -4/4
x=-1

The coordinates (-1, -3) represent the solution of the third system..

For the fourth system:
$\left \{ {{x+y=7} \atop {x-y=-1}} \right.$

Since the coordinates of x are the same and both are positive, we can cancel x by subtracting:
$\left \{ {{x+y=7} \atop {-(x-y=-1)}} \right. \\ \\2y=8$

Divide both sides by 2:
2y/2 = 8/2
y=4

Substitute this into the first equation
x+y=7
x+4=7

Subtract 4 from each side:
x+4-4=7-4
x=3

The coordinates (3, 4) represent the solution to the fourth system.

For the fifth system:
$\left \{ {{y=3x-7} \atop {y=2x-5}} \right.$

Since y is isolated in each equation, we can set them equation to each other:
3x-7=2x-5

Subtract 2x from each side:
3x-7-2x=2x-5-2x
x-7=-5

Add 7 to each side:
x-7+7=-5+7
x=2

Substitute this into the first equation:
y=3x-7
y=3(2)-7
y=6-7
y=-1

The coordinates (2, -1) represent the solution to the fifth system.

7 0

3 years ago

Solve 3[-x + (2 x + 1)2 = x - 1 X=?

Anna007 [38]

Answer:

x=−7/8

Step-by-step explanation:

3 0

3 years ago

CB = 4, CA = 11 , and CE = 8 , what is the length of overline ET ?

leva [86]

Answer:

Step-by-step explanation:

because CE is 8 and the space is equal to ET

5 0

3 years ago

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ipn [44]

A. Will most likely be the answer I might be wrong.

3 0

3 years ago

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