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2 years ago

CB = 4, CA = 11 , and CE = 8 , what is the length of overline ET ?

Mathematics

1 answer:

leva [86]2 years ago

5 0

Answer:

Step-by-step explanation:

because CE is 8 and the space is equal to ET

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What is the measure of ACB please help Im so confused how to get the answer :(

natulia [17]

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2 years ago

Lindsay used two points, (x 1, y 1) and (x 2, y 2), to find the equation of the line, y = mx + b, that passes through the points

Gala2k [10]

Answer:

tb i think its A

Step-by-step explanation:

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3 years ago

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Someone please help!!

Katena32 [7]

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

Step-by-step explanation:

You can find the amount of students each vehicle can carry by representing the two scenarios in equations.

You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.

High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.

High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.

Now, represent these in equations:

$v+6b = 372\\4v + 12b = 780$

We can use substitution to solve this system:

$v + 6b = 372$ can be rewritten as $v = 372 - 6b$ after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

$4(372-6b) + 12b = 780\\1488 - 24b + 12b = 780\\1488 - 12b = 780\\-12b = -708\\b = 59$

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

$v + 6(59) = 372\\v + 354 = 372\\v = 18$

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

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3 years ago

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What is the polynomial function of lowest degree with lead coefficient 1 and roots i, -2 and 2?

lutik1710 [3]

Answer:

Step-by-step explanation:

the polynomial function is; (x - i)(x-2)(x+2)

7 0

3 years ago

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Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

3 0

3 years ago

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