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Nostrana [21]
2 years ago
7

Select the correct answer from each drop-down menu. Graph of proportional relationships. X-axis labeled Number of Plants. Y-axis

labeled Number of Roses. Line begins from origin and goes through plotted closed points at (1, 5), (2, 10), (3, 15), (4, 20). According to the graph, the relationship between the number of rose plants and the number of roses is . Reset Next
Mathematics
1 answer:
spayn [35]2 years ago
7 0

The relationship between the number of plants and the number of roses is a linear relationship.

<h3>What are the characteristics of a linear relationship?</h3>

The given points on the graph are;

(1, 5), (2, 10), (3, 15), (4, 20)

The difference between consecutive x-values is 1, which is constant;

2 - 1 = 3 - 2 = 4 - 3 = 1

Similarly, the difference between consecutive y-values is also a constant, 5;

10 - 5 = 15 - 10 = 20 - 15 = 1

The x-values are the x-coordinates of the points found by using the numbers along the X-axis, while the y-values are the y-coordinates of the points, corresponding to the numbers located along the y-axis

Given that the differences between consecutive terms of the x and y-values are constant, therefore;

  • The relationship between the Number of plants and the Number of Roses is a linear relationship.

Learn more about linear functions and relationships here:

brainly.com/question/4025726

#SPJ1

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Elena-2011 [213]

Answer:

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5y + 5 + 20y = 180 \\ 5y + 20y = 180 - 5 \\ 25y = 175 \\  \frac{25y}{25}  =  \frac{175}{25}  \\ y = 7

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WelpPpPpPP find the value of “x”
stiks02 [169]

Answer:

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Step-by-step explanation:

(x-17) + (7x+5) = 180

  +17          -5       -5

                          175

                           +17

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The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v
Svetllana [295]

Answer:

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by \frac{dV}{dt}

Now,

Given that,

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

⇒\frac{dV}{dt} ∝ \sqrt[3]{V}

Now,

We know that, when we have to remove the Proportionality sign , we just put a constant sign.

Let k be any constant.

So,

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

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