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Butoxors [25]
3 years ago
15

REALLY NEED HELP FAST! Find the value of x if the volume is 384 cm³.

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0

Answer:

b

Step-by-step explanation:

4 * 12 * x = 384

48 * x = 384

x = 8

Bingel [31]3 years ago
6 0

Answer:

8cm because all 3 sides are equal.

Step-by-step explanation:

You might be interested in
Suppose 10 and 6 are common factors of two numbers. What other
kvasek [131]

Answer: 2

Step-by-step explanation:

We can list out their factors

10:1,2,5,10

6:1,2,3,6

Both have the same factors of 2.

5 0
3 years ago
Read 2 more answers
What is the value of 2x^3+7x^2-19x-6 if the value of x is -1
Paul [167]

Answer:

-40

Step-by-step explanation:

Let's input x into all of the slots.

-2^{2}+-7^{2}+19-6

Now, let's solve!

-4-49+19-6

-40

So, the answer is -40!

5 0
3 years ago
1.assume that nominal gdp for 2012 was $700b with a price index of 110 (using 2004 as the base year). what is the real gdp for 2
Nezavi [6.7K]

<span> </span>real GDP = nominal GDP / price index

<span>real GDP (2012)= $700 b/ 1.1= $636.36 b</span>

3 0
4 years ago
PLEASE HELP
sweet-ann [11.9K]

Answer:

m < ANM = 36 degrees.

AM = 9.40 cm to the nearest hundredth.

Perimeter =  94.05 cm to the nearest hundredth.

Step-by-step explanation:

As we have a regular pentagon:

m < ANB = 360 / 5

= 72 degrees

So m < ANM = 1/2 * 72

= 36 degrees.

In the triangle ANM, AN = 16 so

sin 36 = Am / 16

AM =  16 sin36

= 9.4045 cm.

AB = 2 * AM = 18.809 cm

So as all sides are equal:

Perimeter = 5 * 18.809

= 94.05 cm.

4 0
3 years ago
A study was conducted to determine whether there were significant differences between medical students admitted through special
Mekhanik [1.2K]

Answer:

P(X\geq 9)=P(X=9)+P(X=10)

And using the probability mass function we got:

P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383  

P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402  

And replacing we got:

P(X \geq 9) = 0.383 +0.402= 0.785

Step-by-step explanation:

Let X the random variable of interest "number of  students graduated", on this case we now that:  

X \sim Binom(n=10, p=0.913)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X\geq 9)=P(X=9)+P(X=10)

And using the probability mass function we got:

P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383  

P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402  

And replacing we got:

P(X \geq 9) = 0.383 +0.402= 0.785

3 0
4 years ago
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