First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
Answer:
c = 64
Step-by-step explanation:
(a-b)² = a² - 2ab + b²
h²- 16h + c
So, 2ab = 16h
2 * h * b = 16h {as a =h}
b= 16h / 2h
b = 8
c = b² = 8*8 = 64
Angle a = 60
given that all angles of a triangle added together must equal 180
x = -20
-20+80=60
do it again for the other angle measurement
60+60+40=180
therefore, angle A is 60°
B would be correct the -3 x and 3 x cancel out
Answer:
x: 23
y: -46
Step-by-step explanation:
so sorry if this is wrong, but i think thats it
