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4 years ago

What is the perimeter of triangleABC

Mathematics

2 answers:

QveST [7]4 years ago

8 0

The triangle is the question

Sunny_sXe [5.5K]4 years ago

7 0

The triangle in the question

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Choose the value for reflection to place triangle ABC on top of triangle DEF. How did the orange triangle move? The triangle fli

SCORPION-xisa [38]

Answer:

x = 3

Step-by-step explanation:

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3 years ago

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Solve for<br> 9(x + 1) = 25+x

den301095 [7]

Answer:

Step-by-step explanation:

9(x+1)=25+x

9x+9=25+x

9x-x=25-9

8x=16

x=16/8

x=2

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3 years ago

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<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

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3 years ago

Which graph represents the function f(x) = |x|?

Brut [27]

Answer:

Step-by-step explanation:

the first one

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How does a business determine the markup on a product or service?

uysha [10]

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By calculating the profit that will keep the business going

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