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deff fn [24]
3 years ago
11

What is the perimeter of triangleABC

Mathematics
2 answers:
QveST [7]3 years ago
8 0

The triangle is the question

Sunny_sXe [5.5K]3 years ago
7 0

The triangle in the question

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Levart [38]
Use an online converter that you may search for on google. com, and learn the method too
3 0
3 years ago
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Solve the system of equations<br> y=-3/2x+9 <br> 2x+2y=16
ozzi

Answer:

x=2 and y=6

Step-by-step explanation:

5 0
2 years ago
Please explain how to solve this step by step.
Phantasy [73]

Answer:

  (a^8)/(b^9)

Step-by-step explanation:

Two rules of exponents come into play.

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

__

Applying the first rule, we have ...

  (a^3)/(a^-5) × (b^-2)/(b^7) = a^(3 -(-5)) × b^(-2 -7) = a^8 × b^-9

Applying the second rule gives the simplified form ...

  = (a^8)/(b^9)

5 0
2 years ago
Help me please thanks​
Svetach [21]

Answer:

Step-by-step explanation:

To the nearest 10 is 300 - 298

To the nearest 100 is 500 - 549

To the nearest 100 is 700 - 698

3 0
2 years ago
JIMMMMMM
Vitek1552 [10]
>= means greater than or equal to
<= means less than or equal to

---------------------------------------------

Part A

The graph of y >= -3x+3 will have a solid boundary line and the shading will be above the boundary line.

The boundary line y = -3x+3 has a negative slope so it moves down as you read it from left to right. It goes through the points (0,3) and (1,0)

--------------

The graph of y < (3/2)x - 6 will have a dashed or dotted boundary line. The shading is below the boundary.

The graph y = (3/2)x-6 goes through the two points (0,-6) and (2,-3)

--------------

If you graph both y >= -3x+3 and y < (3/2)x - 6 together, you get what you see in the attached image. This solution shaded region is the result of the overlapping prior shaded regions. 

---------------------------------------------

Part B

Plug (x,y) = (-6,3) into each inequality to see if we get a true inequality or not

For the first inequality we have
y >= -3x+3
3 >= -3*(-6)+3
3 >= 18+3
3 >= 21
which is false. The value 3 is not larger or equal to 21. So right off the bat we know that (-6,3) is NOT a solution. It is NOT in the solution region.

Let's check the other inequality just for the sake of completeness
y < (3/2)x - 6
3 < (3/2)*(-6) - 6
3 < -9 - 6
3 < -15
this is also false. The value -15 is smaller than 3, since it is to the left of 3

We're given more evidence that (-6,3) is NOT in the solution area. It is outside of both shaded areas. 

7 0
3 years ago
Read 2 more answers
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