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serious [3.7K]
1 year ago
10

= Graph the solution to the inequality on the number line. |y8|≤2

Mathematics
1 answer:
WINSTONCH [101]1 year ago
5 0

The solution of the absolute inequality |y + 8| ≤ 2 is -10 ≤ y ≤ -6

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given the equation:

|y + 8| ≤ 2

Hence:

y + 8 ≤ 2; and -(y + 8) ≤ 2

y ≤ -6 and y ≥ -10

The solution of the absolute inequality |y + 8| ≤ 2 is -10 ≤ y ≤ -6

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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f(x)=2x-1

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The output is f(x). The input is x.

The prompt says to multiply the input by 2, so 2x.

Then subtract 1 to get f(x).

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5. Translate into an equation. Negative seven less than the product of a
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Answer:

-7-<em>x+-2=-7</em>

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For skewed data displays, the median is often a better esitmate of the center of distribution than the mean, but
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For skewed data displays, the median is often a better estimate of the center of distribution than the mean because the former is unaffected by large numbers.

<h3>What is mean?</h3>

Mean refers to the average of set of two or more numbers.

Mean of a set having 'n'  numbers = \frac{Sum Of 'n' Numbers}{n}

<h3>What is median?</h3>

Median refers to the middle-most value of a list of numbers, arranged either in ascending or descending order.

Median = \left \{ {{\frac{n}{2}^{th}  term, if n = even } \atop( (\frac{n-1}{2}+\frac{n+1}{2})/2)^{th} term, if n = odd   }} \right.

Now,

  • Since it takes the average of all the values in the data set, the mean is the most widely used measure of central tendency.
  • Because it is unaffected by exceptionally big numbers, the median performs better than the mean when analyzing data from skewed distributions.

Hence, For skewed data displays, the median is often a better estimate of the center of distribution than the mean.

To learn more about mean and median, refer to the link:brainly.com/question/6281520

#SPJ4

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1 year ago
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