s=1/23
given equation in term of s is 12+3/2s-1/2-3/4s=5/4s
to solve this first we need to take LCM on left hand side and right hand side we can rewrite given equation as 12/1+3/2s-1/2-3/4s=5/4s now taking LCM of {1,2s,2,4s,4s} is 4s then the equation becomes 48s/4s+6/4s-2s/4s-3/4s=5/4s
(48s+6-2s-3) /4s=5/4s now cancel out denominator of both side we get 48s+6-2s-3=5 this implies 46s+3=5
46s=2
s=1/23
Hence the value of s is 1/23
learn more about LCM here brainly.com/question/8463488
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