The root of an equation f(x) is the x value(s) for which f(x) = 0.
So, if you have f(x) = 6x + 3, to find its root(s), you do 0 = 6x + 3, and then
0 - 3 = 6x + 3 - 3
-3 = 6x + 0
-3 = 6x
-3/6 = 6x/6
-1/2 = x
x = -1/2 is the one and only root (Linear functions will always have 0 or 1 root. They will have zero roots if they are horizontal lines of the form y = c, where c is any constant, and they will have one root if they are of the form y = mx + b, where m is not 0.)
Answer:
~8.9%
Step-by-step explanation:
sorry but I don't understand the question.
The expression - x - 9x^2 + 12x^2 + 7 has 4 terms:
-x, -9x^2, 12x^2, 7
Like terms are:
-9x^2, 12x^2